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Vlad1618 [11]
3 years ago
11

Which structural feature of carbon dioxide contributes to its low melting point?

Chemistry
1 answer:
antoniya [11.8K]3 years ago
8 0
 <span>Because it has very weak intermolecular meaning it takes little energy to break them and turn it into a gas</span>
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It's not, if it were it would be ice. The water is a bit warmer.
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What are the dependent and independent variables? (Picture^^)
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Answer:

X axis shows the independent and Y axis shows the dependent.

Explanation:

  • As the independent variable is always plotted on the X-axis of the graph the Y-axis shows the dependent variable that is affected by the X variables Time is an independent variable and is always shown along the X-axis.  
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What is the binding energy of one mole of if the mass defect is 1.908 g/mol?
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3 years ago
Determine the rate law and the value of k for the following reaction using the data provided.CO(g) Cl2(g) → COCl2(g)[CO]i (M)[Cl
marshall27 [118]

<u>Answer:</u> The rate law expression is \text{Rate}=k[CO]^1[Cl_2]^{\frac{3}{2}} and value of 'k' is 11.04M^{-\frac{7}{2}}s^{-1}

<u>Explanation:</u>

Rate law is defined as the expression which expresses the rate of the reaction in terms of molar concentration of the reactants with each term raised to the power their stoichiometric coefficient of that reactant in the balanced chemical equation.

For the given chemical equation:

CO(g)+Cl_2(g)\rightarrow COCl_2(g)

Rate law expression for the reaction:

\text{Rate}=k[CO]^a[Cl_2]^b

where,

a = order with respect to carbon monoxide

b = order with respect to chlorine

  • Expression for rate law for first observation:

0.696=k(0.25)^a(0.40)^b       ....(1)

  • Expression for rate law for second observation:

1.970=k(0.25)^a(0.80)^b       ....(2)

  • Expression for rate law for third observation:

3.94=k(0.50)^a(0.80)^b       ....(3)

Dividing 2 from 3, we get:

\frac{3.94}{1.970}=\frac{(0.50)^a(0.80)^b}{(0.50)^a(0.80)^b}\\\\2=2^a\\a=1

Dividing 1 from 2, we get:

\frac{1.970}{0.696}=\frac{(0.25)^a(0.80)^b}{(0.25)^a(0.40)^b}\\\\2.83=2^b\\b=1.5

Thus, the rate law becomes:

\text{Rate}=k[CO]^1[Cl_2]^{\frac{3}{2}}

Now, calculating the value of 'k' by using any expression.

Putting values in equation 1, we get:

0.696=k[0.25]^1[0.40]^{\frac{3}{2}}\\\\k=11.04M^{-\frac{7}{2}}s^{-1}

Hence, the rate law expression is \text{Rate}=k[CO]^1[Cl_2]^{\frac{3}{2}} and value of 'k' is 11.04M^{-\frac{7}{2}}s^{-1}

6 0
4 years ago
Match the term with its description.
MrMuchimi
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</span>The term alkaline is related to <span>compound that increases the hydroxide ions (OH−) when it is dissolved in a solution.
</span>
pH refers to <span>a value from 0 to 14 that is used to specify how acidic or basic a compound is when it is dissolved in water

An </span>ion is <span>an atom or molecule that has a positive or negative charge.</span>
7 0
4 years ago
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