PH becomes lower when the H+ ion concentration increases.
<span>pH becomes higher when the H+ ion concentration decreases. </span>
<span>pH becomes lower when the OH- ion concentration decreases. </span>
pH becomes higher when the OH- ion concentration increases.
Hope this helps!
Density volume mass intensive and extensive
Answer:
no
Explanation:
no, because it will make me sick. And my doctor said that just because something is brown and squishy it isn't chocolate.
Explanation:
It is known that relation between 
, 
, and pH is as follows.
![E_{cell} = E^{o}_{cell} - (\frac{0.0591}{n}) \times log[H^{+}] ](https://tex.z-dn.net/?f=E_%7Bcell%7D%20%3D%20E%5E%7Bo%7D_%7Bcell%7D%20-%20%28%5Cfrac%7B0.0591%7D%7Bn%7D%29%20%5Ctimes%20log%5BH%5E%7B%2B%7D%5D%0A)
Also, it is known that for hydrogen is equal to zero.
Hence, substituting the given values into the above equation as follows.
0.238 V = 0 - (\frac{0.0591}{1}) \times log[H^{+}]
[/tex]
![-log[H^{+}]](https://tex.z-dn.net/?f=-log%5BH%5E%7B%2B%7D%5D)
= 4.03
![[H^{+}]](https://tex.z-dn.net/?f=%5BH%5E%7B%2B%7D%5D)
= antilog 4.03
= 3.5
As, pH = .
Thus, we can conclude that pH of the given unknown solution at 298 K is 3.5.
Answer:
Q = 57934.8 J
Explanation:
Given data:
Mass of water = 180.0 g
Initial temperature = 19°C
Fina temperature = 96°C
Specific heat capacity of water = 4.18 J/g.°C
Heat absorbed = ?
Solution:
Formula:
Q = m.c. ΔT
Q = amount of heat absorbed or released
m = mass of given substance
c = specific heat capacity of substance
ΔT = change in temperature
ΔT = 96°C - 19°C
ΔT = 77°C
Q = 180.0 g×4.18 J/g.°C×77°C
Q = 57934.8 J
