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2 years ago

6

The base of a triangular field is three times its height. If the cost of cultivating the feild at $36 per hectare is $486, find

its base and height.
Please explain also

1 answer:

Anna [14]2 years ago

5 0

Answer:

Formula of the area of triangle = 1/2 × b × h (where 'b' is the base and 'h' is the height)

1 hectare = $36

$486 = 13.5 hectares

13.5 hectares = 1/2 × b × h

To get b × h, you use the reverse of the formula. Hence:

13.5 = 1/2 × b × h

13.5 ÷ 1/2 = b × h

= 27

27 is b × h.

The question states that the base is three times the height. Hence:

b = 3u

h = 1u

b × h = 27

= 3u × 1u

Thus, we need to find one value which is three times the other, in order to get a product of 27.

Factors of 27:

1 × 27

3 × 9

9 is three times of 3. Thus, the base is 9, while the height is 3.

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AysviL [449]

M < 1 = 140
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40 + 90 + <3 = 180
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3 years ago

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STALIN [3.7K]

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Ymorist [56]

Complementary angles add up to 90 degrees.
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2 years ago

Use Gaussian elimination to write each system in triangular form

Feliz [49]

Answer:

To see the steps to the diagonal form see the step-by-step explanation. The solution to the system is $x = -\frac{1}{9}$ , $y= -\frac{1}{9}$ , $z= \frac{4}{9}$ and $w = \frac{7}{9}$

Step-by-step explanation:

Gauss elimination method consists in reducing the matrix to a upper triangular one by using three different types of row operations (this is why the method is also called row reduction method). The three elementary row operations are:

Swapping two rows
Multiplying a row by a nonzero number
Adding a multiple of one row to another row

To solve the system using the Gauss elimination method we need to write the augmented matrix of the system. For the given system, this matrix is:

$\left[\begin{array}{cccc|c}1 & 1 & 1 & 1 & 1 \\1 & 1 & 0 & -1 & -1 \\-1 & 1 & 1 & 2 & 2 \\1 & 2 & -1 & 1 & 0\end{array}\right]$

For this matrix we need to perform the following row operations:

$R_2 - 1 R_1 \rightarrow R_2$ (multiply 1 row by 1 and subtract it from 2 row)
$R_3 + 1 R_1 \rightarrow R_3$ (multiply 1 row by 1 and add it to 3 row)
$R_4 - 1 R_1 \rightarrow R_4$ (multiply 1 row by 1 and subtract it from 4 row)

$R_2 \leftrightarrow R_3$ (interchange the 2 and 3 rows)

$R_2 / 2 \rightarrow R_2$ (divide the 2 row by 2)
$R_1 - 1 R_2 \rightarrow R_1$ (multiply 2 row by 1 and subtract it from 1 row)
$R_4 - 1 R_2 \rightarrow R_4$ (multiply 2 row by 1 and subtract it from 4 row)
$R_3 \cdot ( -1) \rightarrow R_3$ (multiply the 3 row by -1)
$R_2 - 1 R_3 \rightarrow R_2$ (multiply 3 row by 1 and subtract it from 2 row)
$R_4 + 3 R_3 \rightarrow R_4$ (multiply 3 row by 3 and add it to 4 row)
$R_4 / 4.5 \rightarrow R_4$ (divide the 4 row by 4.5)

After this step, the system has an upper triangular form

The triangular matrix looks like:

$\left[\begin{array}{cccc|c}1 & 0 & 0 & -0.5 & -0.5 \\0 & 1 & 0 & -0.5 & -0.5\\0 & 0 & 1 & 2 & 2 \\0 & 0 & 0 & 1 & \frac{7}{9}\end{array}\right]$

If you later perform the following operations you can find the solution to the system.

$R_1 + 0.5 R_4 \rightarrow R_1$ (multiply 4 row by 0.5 and add it to 1 row)
$R_2 + 0.5 R_4 \rightarrow R_2$ (multiply 4 row by 0.5 and add it to 2 row)
$R_3 - 2 R_4 \rightarrow R_3$ (multiply 4 row by 2 and subtract it from 3 row)

After this operations, the matrix should look like:

$\left[\begin{array}{cccc|c}1 & 0 & 0 & 0 & -\frac{1}{9} \\0 & 1 & 0 & 0 & -\frac{1}{9}\\0 & 0 & 1 & 0 & \frac{4}{9} \\0 & 0 & 0 & 1 & \frac{7}{9}\end{array}\right]$

Thus, the solution is:

$x = -\frac{1}{9}$ , $y= -\frac{1}{9}$ , $z= \frac{4}{9}$ and $w = \frac{7}{9}$

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3 years ago

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Anarel [89]

Answer:

38 %

Step-by-step explanation:

1. Percent of lawns mowed

$\text{Percent} = \dfrac{\text{Lawns mowed}}{\text{No. of lawns}} \times 100 \% = \dfrac{37}{60} \times 100 \% = 62 \%}$

2. Percent of lawns unmowed

% Unmowed = 100 % - 62 % = 38 %

Henry still needs to mow 38 % of the lawns.

7 0

3 years ago