How does the position of an object relate to the energy stored in an object?
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To solve this problem it is necessary to apply the concepts related to the Rotational Force described from the equilibrium and Newton's second law.
When there is equilibrium, the Force generated by the tension is equivalent to the Force of the Weight. However in rotation, the Weight must be equivalent to the Centrifugal Force and the tension, in other words:
Where
Angular velocity is equal to the Period, at this case Earth's period
Radius of the Earth
m = mass
= Force of Tension
Newton's second law
Replacing and re-arrange to find the Tension we have,
Therefore when Sneezy is on the equator he is in a circular orbit with a Force of tension of 503.26N
The final common speed of the two carts will be 69.3 m/sec.The momentum conservation principle is applied.
<h3>What is the law of conservation of momentum?</h3>According to the law of conservation of momentum, the momentum of the body before the collision is always equal to the momentum of the body after the collision.
Unit conversion:
1 metric tons = 1000 kg
Given data;
m₁= 11.6 metric ton =11600 kg
m₂ = 23.2 metric ton = 23200 kg
Let v represent the combined velocity of the two carts once they are connected, and let u represent the starting velocity of cart 1 when it reaches the bottom.
Considering energy conservation;
From the conservation of momentum principle;
Hence, the final common speed of the two carts will be 69.3 m/sec.
To learn more about the law of conservation of momentum refer;
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