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mylen [45]
3 years ago
15

If an object travels 245 km in 5 hours, what was the speed of the object?

Physics
1 answer:
seraphim [82]3 years ago
5 0

Answer:

49kmph

Explanation:

speed=distance/time = 245/5

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A massless rope passes over a massless pulley suspended from the ceiling. A 4-kg block is attached to one end and a 5-kg block i
borishaifa [10]

The acceleration on the 5kg block is 1.088m/s^2

Data;

  • mass(a) = 4kg
  • mass (b) = 5kg
  • acceleration of the 5kg block.
<h3>The Acceleration on the 5kg block</h3>

To solve this question, we just need to use Newton's second law of motion which states that "the time rate of change of the momentum of a body is equal in both magnitude and direction to the force imposed on it."

F_n_e_t = M_t_o_t_a_l * a\\F = ma\\F_n_e_t = mg\\

But then the force on both sides will be

mg = ma\\5g - 4g= (4+5) a\\(5-4)g = 9a\\g = 9a\\a = \frac{g}{9} \\a = \frac{9.80}{9} \\a = 1.088 m/s^2

The acceleration on the 5kg block is 1.088m/s^2

Learn more on newton's second law of motion here;

brainly.com/question/3050695

brainly.com/question/13447525

4 0
2 years ago
If a powerlifter raises a 1000 N weight a distance of 2.0 meters in 0.5 seconds, what is his power output?
Ilya [14]
Power =Force * Velocity

Velocity = Distance/Time = 2/0.5 = 4 m/s

Therefore,

P = 1000*4 =  4000 W = 4 kW
3 0
3 years ago
Read 2 more answers
Since acids are so corrosive they are not found anywhere in the human body true/false
pantera1 [17]

the answer is in fact True

5 0
3 years ago
Read 2 more answers
Taking the resistivity of platinoid as 3.3 x 10-7 m, find the resistance of 7.0 m of platinoid wire of average diameter 0.14 cm.
mr_godi [17]

Answer:

1.5 \Omega

Explanation:

The resistance of a wire is given by the equation:

R=\rho \frac{L}{A}

where

\rho is the resistivity of the material

L is the length of the wire

A is the cross-sectional area of the wire

In this problem, we have a wire of platinoid, whose resistivity is

\rho = 3.3\cdot 10^{-7} \Omega m

The length of the wire is

L = 7.0 m

And its radius is

r=\frac{0.14 cm}{2}=0.07 cm = 7\cdot 10^{-4} m, so the cross-sectional area is

A=\pi r^2=\pi(7\cdot 10^{-4})^2=1.54\cdot 10^{-6}m^2

Solving for R, we find the resistance of the wire:

R=(3.3\cdot 10^{-7})\frac{7.0}{1.54\cdot 10^{-6}}=1.5 \Omega

3 0
3 years ago
What initially unknown quantity, together with the wavelength, is sufficient to calculate the stopping potential for 400 nmnm li
kondaur [170]

Answer:

The initially known quantity, together with the wavelength, that is sufficient to calculate the stopping potential for electrons from the surface of a metal is called the WORK FUNCTION.

Explanation:

The stopping potential is defined as the potential that is required to stop electrons from being ejected from the surface of a metal when light with energy greater than the metal's work function/work potential is incident on the metal.

Given that light is known to be made up of photons, which carry energy in packets according to the frequencies of the light.

The photoelectric phenomenon explains that when light of a certain frequency that corresponds to an energy level that is higher than a metal's work function is incident on a metal, it will lead to electrons being ejected from the surface of the metal. The energy of the ejected electrons is then proportional to the difference between the energy level of the photons and the metal's work function.

Basically, it is the excess energy after overcoming the work function that rejects the electrons.

So, to prevent this excess energy from ejecting electrons from a metal's surface, an energy thay matches this excess must be in place to stop electrons from coming out. This energy/potential required to stop the ejection of electrons, is called the stopping potential.

The stopping potential is given as

eV₀ = hf - ϕ

The stopping potential (eV₀) them depends on the hf and the ϕ.

hf is the energy of the photons, where h is Planck's constant and f is the photons' frequency which is further given as

f = (c/λ)

c = speed of light (speed of the photons)

λ = wavelength of the photons.

The other quantity, ϕ, is the metal's work function; the amount of energy needed to be overcome by the photons before ejection of electrons is possible. It is the minimum energy that the light photoms must possess to even stand a chance of being able to eject electrons from a metal's surface.

So, the stopping potential is the difference between the energy of the photons (obtained using the photons' frequency, wavelength and/or speed) and the metal's work function.

Hope this Helps!!!!

3 0
4 years ago
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