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Basile [38]
3 years ago
7

A __________ has distinct properties and composition that never vary. A) solution B) molecule C) pure substance D) heterogeneous

mixture
Physics
2 answers:
Nataly [62]3 years ago
8 0
Matter is defined as anything that has mass and occupies space, it may be classified into three states, solid, liquids or gases. Molecules is the smallest particle of an element that has the chemical properties of the element or the compound. it contains two or more atoms that are joined together. A pure substance is a matter that has distinct properties and a composition that does not vary from sample to sample. Thus the correct answer is C
sweet-ann [11.9K]3 years ago
6 0

Answer:

C) pure substance

Explanation:

Pure substance is any substance formed by only one type of molecule, of invariable and homogeneous chemical composition, which has constant physical and chemical properties. Pure substance may exist in more than one phase, but in such cases the phase composition will be the same.

In short, pure substance is all material with the following characteristics:

  • Structural units (molecules, ionic assemblies) chemically equal to each other.
  • Fixed composition, resulting in fixed properties such as density, melting and boiling point, etc. That is, these substance have distinct properties and composition that never vary.
  • The temperature remains unchanged from the beginning to the end of all your physical state changes (melting, boiling, solidifying, etc.).
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Bus starts from rest if the acceleration of the bus is 0.5 MS square what will be the velocity at the end of two minutes and wha
beks73 [17]

Answer:

1. 60 m/s.

2. 3600 m.

Explanation:

The following data were obtained from the question:

Initial velocity (u) = 0

Acceleration (a) = 0.5 m/s²

Time (t) = 2 mins

Final Velocity (v) =?

Distance travelled (s) =?

1. Determination of the velocity at the end of 2 minutes.

Initial velocity (u) = 0

Acceleration (a) = 0.5 m/s²

Time (t) = 2 mins = 2 x 60 = 120 secs

Final Velocity (v) =?

v = u + at

v = 0 + (0.5 x 120)

v = 60 m/s

Therefore, the velocity at the end of 2 minutes is 60 m/s.

2. Determination of the distance travelled.

Initial velocity (u) = 0

Acceleration (a) = 0.5 m/s²

Final velocity (v) = 60 m/s

Distance travelled (s) =..?

v² = u² + 2as

60² = 0 + 2 x 0.5 x s

3600 = 1 x s

s = 3600 m

Therefore, the distance travelled is 3600 m.

6 0
3 years ago
Referring to the sketch of a planet around the sun, Area A is three times that of Area B. Compare the times required for the pla
charle [14.2K]

Answer:

tA is three times tB

Explanation:

4 0
3 years ago
Read 2 more answers
Points A and B lie within a region of space where there is a uniform electric field that has no x- or z-component; only the y-co
liraira [26]

Answer:

(a) Ey is negative

(b) The magnitude of the electric field is E = 171.429 V/m

(c) The potential difference between points B and C is 17.1429 V

Explanation:

(a) Here, we have the potentials given by;

V_A - V_B = +12.0V with point A at y = 8.00 cm and point B at point y = 15.0 cm

where point B is at a higher potential than point A, that is the electric potential is from;

B with y = 15.0 cm to A with y = 8.0 cm which means

E_y decreases as y increases or E_y  is negative.

(b) The magnitude of the electric field is given by

The work done to move a charge from B to A is

W_{BA} = - \Delta U where

\Delta U = U_a -U_b = q_0E(y_b-y_a)

V_{BA} = \frac{\Delta U}{q_0} = \frac{q_0E(y_b-y_a)}{q_0}  = E(y_b-y_a)

∴ E = \frac{V_{BA}}{(y_b-y_a)}

E = \frac{12 \hspace{0.09cm}V}{(0.015\hspace{0.09cm} m -0.008\hspace{0.09cm} m)}

E = 171.429 V/m

(c) Here we have point C x = 5.00 cm and y = 5.00 cm

Therefore we have the distance from B to C given by

y_b-y_c = 15.00 \hspace{0.09cm}cm - 5.00  \hspace{0.09cm}cm = 10.00 \hspace{0.09cm} cm

Where 10.00 cm = 0.01 m

E = V/Δy

Therefore, V = Δy·E

For V_{BC}, Δy = y_b-y_c  = 0.01 \hspace{0.09cm} m and we have,

V_{BC} = E\times (y_b-y_c)

V_{BC} = 171.429\times (0.015-0.005) = 17.1429\hspace{0.09cm}V

7 0
3 years ago
Urgent!!! 50 points to who answers this question in a clear and simple explanation :
lina2011 [118]

You only need to use the right two simple formulas:

Work = (force) x (distance)

-- A mass that weighs 500N is being pulled down by gravity with a force of 500N.  (That's what "weighs" means.)  If you want to lift it straight up against gravity, you have to lift with a force of 500N.  

The WORK you do on the mass is (500N) x (height you raise it to).


Power = (work) / (time)

-- 4,000 watts = (500N x Height) / 20 seconds

From here, the rest is just algebra ... pulling the height out of this equation:

Multiply each side by (20 sec):

(500N x height) = (4,000 watts x 20 sec)

Divide each side by (500N):

Height = (4,000 watts x 20 sec) / (500N)

Height = (4,000 x 20 / 500) (watt x second / Newton)

(Remember that "watt-second" = "Joule",

and "Joule" = "Newton-meter".)  

<em>Height = 160 meters</em>

4 0
3 years ago
The moment of inertia of a thin uniform rod of mass M and length L about an Axis perpendicular to the rod through its Centre is
sleet_krkn [62]

Answer:

I = I₀ + M(L/2)²

Explanation:

Given that the moment of inertia of a thin uniform rod of mass M and length L about an Axis perpendicular to the rod through its Centre is I₀.

The parallel axis theorem for moment of inertia states that the moment of inertia of a body about an axis passing through the centre of mass is equal to the sum of the moment of inertia of the body about an axis passing through the centre of mass and the product of mass and the square of the distance between the two axes.

The moment of inertia of the body about an axis passing through the centre of mass is given to be I₀

The distance between the two axes is L/2 (total length of the rod divided by 2

From the parallel axis theorem we have

I = I₀ + M(L/2)²

5 0
3 years ago
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