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Basile [38]
3 years ago
7

A __________ has distinct properties and composition that never vary. A) solution B) molecule C) pure substance D) heterogeneous

mixture
Physics
2 answers:
Nataly [62]3 years ago
8 0
Matter is defined as anything that has mass and occupies space, it may be classified into three states, solid, liquids or gases. Molecules is the smallest particle of an element that has the chemical properties of the element or the compound. it contains two or more atoms that are joined together. A pure substance is a matter that has distinct properties and a composition that does not vary from sample to sample. Thus the correct answer is C
sweet-ann [11.9K]3 years ago
6 0

Answer:

C) pure substance

Explanation:

Pure substance is any substance formed by only one type of molecule, of invariable and homogeneous chemical composition, which has constant physical and chemical properties. Pure substance may exist in more than one phase, but in such cases the phase composition will be the same.

In short, pure substance is all material with the following characteristics:

  • Structural units (molecules, ionic assemblies) chemically equal to each other.
  • Fixed composition, resulting in fixed properties such as density, melting and boiling point, etc. That is, these substance have distinct properties and composition that never vary.
  • The temperature remains unchanged from the beginning to the end of all your physical state changes (melting, boiling, solidifying, etc.).
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A .005kg projectile leaves a 1500kg launcher with a velocity of 750 m/s. What is the recoil velocity of the projectile
docker41 [41]

Answer:

The recoil velocity of the projectile is 0.0025m/s

Explanation:

Given:

Mass of the projectile =0.005kg

Mass of the launcher = 1500kg

Velocity =  750 m/s.

To Find:

The recoil velocity of the projectile = ?

Solution:

The recoil velocity is the obtained by dividing the "recoil momentum"  by the "mass of the recoil body".  The recoil momentum is equal to the momentum of the other body. The momentum of the other body is equal to it mass times its velocity.

Lets find the recoil momentum,

Recoil momentum = mass of the projectile X velocity

Recoil momentum =0.005 \times 750

Recoil momentum = 3.75

Now Recoil Velocity,

Recoil Velocity = \frac{\text { Recoil Momentum}}{\text {Mass of the launcher}}

Recoil Velocity = \frac{ 3.75}{1500}

Recoil Velocity = 0.0025m/s

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4 years ago
State two (2) examples of osmosis occurring in everyday life
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When you keep raisin in water and the raisin gets puffed.
Movement of salt-water in animal cell across our cell membrane.
3 0
3 years ago
Two parallel wires are separated by 5.60 cm, each carrying 2.65 A of current in the same direction. (a) What is the magnitude of
ololo11 [35]

Explanation:

It is given that,

The separation between two parallel wires, r = 5.6 cm = 0.056 m

Current in both the wires is 2.65 A

(a) We need to find the magnitude of the force per unit length between the wires. It can be given by :

\dfrac{F}{l}=\dfrac{\mu_o I_1I_2}{2\pi r}\\\\\dfrac{F}{l}=\dfrac{4\pi \times 10^{-7}\times 2.65\times 2.65}{2\pi \times 0.056}\\\\\dfrac{F}{l}=2.5\times 10^{-5}\ N/m

(b) As the current is in same direction, the wires will attract each other.

5 0
3 years ago
The weight of an object is the same on two different planets. The mass of planet A is only sixty percent that of planet B. Find
natka813 [3]

Answer:

0.775

Explanation:

The weight of an object on a planet is equal to the gravitational force exerted by the planet on the object:

F=G\frac{Mm}{R^2}

where

G is the gravitational constant

M is the mass of the planet

m is the mass of the object

R is the radius of the planet

For planet A, the weight of the object is

F_A=G\frac{M_Am}{R_A^2}

For planet B,

F_B=G\frac{M_Bm}{R_B^2}

We also know that the weight of the object on the two planets is the same, so

F_A = F_B

So we can write

G\frac{M_Am}{R_A^2} = G\frac{M_Bm}{R_B^2}

We also know that the mass of planet A is only sixty percent that of planet B, so

M_A = 0.60 M_B

Substituting,

G\frac{0.60 M_Bm}{R_A^2} = G\frac{M_Bm}{R_B^2}

Now we can elimanate G, MB and m from the equation, and we get

\frac{0.60}{R_A^2}=\frac{1}{R_B^2}

So the ratio between the radii of the two planets is

\frac{R_A}{R_B}=\sqrt{0.60}=0.775

6 0
3 years ago
Please need help on these
Alborosie

question 6 is global warming and question 7 is carbon dioxide

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3 years ago
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