Answer:
The recoil velocity of the projectile is 0.0025m/s
Explanation:
Given:
Mass of the projectile =0.005kg
Mass of the launcher = 1500kg
Velocity = 750 m/s.
To Find:
The recoil velocity of the projectile = ?
Solution:
The recoil velocity is the obtained by dividing the "recoil momentum" by the "mass of the recoil body". The recoil momentum is equal to the momentum of the other body.
The momentum of the other body is equal to it mass times its velocity.
Lets find the recoil momentum,
Recoil momentum = mass of the projectile X velocity
Recoil momentum =
Recoil momentum = 3.75
Now Recoil Velocity,
Recoil Velocity = 
Recoil Velocity = 
Recoil Velocity = 0.0025m/s
When you keep raisin in water and the raisin gets puffed.
Movement of salt-water in animal cell across our cell membrane.
Explanation:
It is given that,
The separation between two parallel wires, r = 5.6 cm = 0.056 m
Current in both the wires is 2.65 A
(a) We need to find the magnitude of the force per unit length between the wires. It can be given by :

(b) As the current is in same direction, the wires will attract each other.
Answer:
0.775
Explanation:
The weight of an object on a planet is equal to the gravitational force exerted by the planet on the object:

where
G is the gravitational constant
M is the mass of the planet
m is the mass of the object
R is the radius of the planet
For planet A, the weight of the object is

For planet B,

We also know that the weight of the object on the two planets is the same, so

So we can write

We also know that the mass of planet A is only sixty percent that of planet B, so

Substituting,

Now we can elimanate G, MB and m from the equation, and we get

So the ratio between the radii of the two planets is

question 6 is global warming and question 7 is carbon dioxide