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3 years ago

Un automóvil se desplaza 30 1/5 millas en 2/3 de hora. ¿Cuál es la velocidad promedio en millas por hora, del automóvil?

2 answers:

3 0

Queremos encontrar la velocidad promedio de un automóvil dado que conocemos cuanto se desplaza y cuanto tarda en realizar ese desplazamiento. Veremos que la velocidad promedio es 45.3 millas por hora.

Recordar que definimos velocidad promedio como el cociente entre la distancia recorrida y el tiempo que se tarda en recorrer esa distancia.

Aca tenemos:

Desplazamiento = (30 + 1/5) cm

Tiempo = (2/3 horas)

Entonces la velocidad esta dada por:

$V = \frac{(30 + 1/5)mi}{2/3 h} = \frac{(151/5)mi}{2/3 h} = 45.3 mi/h$

Asi podemos concluir que la velocidad promedio es 45.3 millas por hora.

Sí quieres aprender más sobre velocidad, puedes leer:

brainly.com/question/25316464

Salsk061 [2.6K]3 years ago

3 0

The speed of the automobile is 45.3 miles per hour

The formula for calculating the speed of the automobile is expressed as:

Speed = Distance/Time

Given the following parameters:

Distances = 30.2 miles
Time = 2/3 hour

Substitute into the formula:

Speed = 30.2 * 3/2

Speed = 15.1 * 3

Speed = 45.3 miles/hr

Hence the speed of the automobile is 45.3 miles per hour

Learn more on speed here:brainly.com/question/4931057

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In a binomial distribution, n = 8 and π=0.36. Find the probabilities of the following events. (Round your answers to 4 decimal p

skelet666 [1.2K]

Answer:

$\mathbf{P(X=5) =0.0888}$

P(x ≤ 5 ) = 0.9707

P ( x ≥ 6) = 0.0293

Step-by-step explanation:

The probability of a binomial mass distribution can be expressed with the formula:

$\mathtt{P(X=x) =(^{n}_{x} ) \ \pi^x \ (1-\pi)^{n-x}}$

$\mathtt{P(X=x) =(\dfrac{n!}{x!(n-x)!} ) \ \pi^x \ (1-\pi)^{n-x}}$

where;

n = 8 and π = 0.36

For x = 5

The probability $\mathtt{P(X=5) =(\dfrac{8!}{5!(8-5)!} ) \ 0.36^5 \ (1-0.36)^{8-5}}$

$\mathtt{P(X=5) =(\dfrac{8!}{5!(3)!} ) \ 0.36^5 \ (0.64)^{3}}$

$\mathtt{P(X=5) =(\dfrac{8 \times 7 \times 6 \times 5!}{5!(3)!} ) \times \ 0.0060466 \ \times 0.262144}$

$\mathtt{P(X=5) =(\dfrac{8 \times 7 \times 6 }{3 \times 2 \times 1} ) \times \ 0.0060466 \ \times 0.262144}$

$\mathtt{P(X=5) =({8 \times 7 } ) \times \ 0.0060466 \ \times 0.262144}$

$\mathtt{P(X=5) =0.0887645}$

$\mathbf{P(X=5) =0.0888}$ to 4 decimal places

b. x ≤ 5

The probability of P ( x ≤ 5) $\mathtt{P(x \leq 5) = P(x = 0)+ P(x = 1)+ P(x = 2)+ P(x = 3)+ P(x = 4)+ P(x = 5})$

${P(x \leq 5) = ( \dfrac{8!}{0!(8!)} \times (0.36)^0 \times (1-0.36)^8 \ ) + \dfrac{8!}{1!(7!)} \times (0.36)^1 \times (1-0.36)^7 \ +$ $\dfrac{8!}{2!(6!)} \times (0.36)^2 \times (1-0.36)^6 \ + \dfrac{8!}{3!(5!)} \times (0.36)^3 \times (1-0.36)^5 + \dfrac{8!}{4!(4!)} \times (0.36)^4 \times (1-0.36)^4 \ + \dfrac{8!}{5!(3!)} \times (0.36)^5 \times (1-0.36)^3 \ )$