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marysya [2.9K]
2 years ago
11

The basic building blocks of java is known asReply fast! plzzzzzzzzzzz!!!

Computers and Technology
1 answer:
Nadya [2.5K]2 years ago
8 0

Answer:

A class is the basic building block in Java.

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Call 334-399-4201 to annoyed my mom
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Michelle wants to define the scope of a software development project for the benefit of her company. How does defining the scope
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Write a program that plays the popular scissor-rockpaper game. (A scissor can cut a paper, a rock can knock a scissor, and a pap
kolbaska11 [484]

Answer:

import random

computer = random.randint(0, 2)

user = int(input("scissor (0), rock (1), paper (2): "))

if computer == 0:

   if user == 0:

       print("The computer is scissor. You are scissor too. It is a draw")

   elif user == 1:

       print("The computer is scissor. You are rock. You won")

   elif user == 2:

       print("The computer is scissor. You are paper. Computer won")

elif computer == 1:

   if user == 0:

       print("The computer is rock. You are scissor. Computer won")

   elif user == 1:

       print("The computer is rock. You are rock too. It is a draw")

   elif user == 2:

       print("The computer is rock. You are paper. You won")

elif computer == 2:

   if user == 0:

       print("The computer is paper. You are scissor. You won")

   elif user == 1:

       print("The computer is paper. You are rock. Computer won")

   elif user == 2:

       print("The computer is paper. You are paper too. It is a draw")

Explanation:

*The code is in Python.

Import the random to be able to generate number number

Generate a random number between 0 and 2 (inclusive) using randint() method and set it to the computer variable

Ask the user to enter a number and set it to the user variable

Check the value of computer the computer variable:

If it is 0, check the value of user variable. If user is 0, it is a draw. If user is 1, user wins. If user is 2, computer wins

If it is 1, check the value of user variable. If user is 0, computer wins. If user is 1, it is a draw. If user is 2, user wins

If it is 2, check the value of user variable. If user is 0, user wins. If user is 1, computer wins. If user is 2, it is a draw

8 0
2 years ago
If classes C1 and C2 both implement an interface Cint, which has a method whichIsIt, and if C1 c = new C1( ); is performed at on
Assoli18 [71]

Answer:

FALSE

Explanation:

Because C1 and C2 implement the same interface, they both implement whichIsIt. The variable c is known as a polymorphic variable, meaning that it can change from being an C1 to a C2. So, the message c.whichIsIt( ); may invoke C1's whichIsIt or C2's whichIsIt. This can only be known at runtime.

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