Question

A sample of aluminum is placed in a 25-ml graduated cylinder containing 10.0 ml of water. the level of the water rises to 18.0 ml. aluminum has a density of 2.7 g/ml. calculate the mass of the sample.

Answer 1

To determine the mass of the sample, first find the volume difference after and before the aluminum was placed, the volume change is equal to the volume of the submerged object, in this case aluminum.

Then knowing volume of aluminum and the density of it, we can solve for the mass.

D = m/v

Dv = m

2.7 g/ml • 8 ml = 21.6 grams.

Answer 2

Answer:

The mass of the aluminium sample is 21.6 grams.

Explanation:

Mass of the sample of aluminium = m

Volume of the aluminium = V

Density of the aluminum = d = 2.7 g/mL

Initial level of water mark in cylinder = 10.0 mL

Final level of water after sample is immersed = 18.0 mL

Volume occupied by the sample = V = 18.0 mL - 10.0 mL = 8.0 mL

$Density=\frac{Mass}{Volume}$

$Mass=Density\times Volume = d\times V$

$m=2.7 g/mL\times 8 mL= 21.6 g$

The mass of the aluminium sample is 21.6 grams.