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PSYCHO15rus [73]
3 years ago
9

In 1895, X-rays were accidentally discovered during a scientific experiment. Today, X-rays are used to screen luggage in airport

s. This is an example of _____.
society influencing technology
society influencing science
science influencing technology
science influencing society
Chemistry
1 answer:
allsm [11]3 years ago
4 0
Thanks for your question!

The answer is science influencing technology, as it was discovered in a science experiment. It doesn't really influence society as much because it doesn't influence the way people act, just the how things work.

Hope this helped!
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Molar mass for C 3 H 6 (O H)2
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Answer:

The answer is 76.0944

Explanation:

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3 years ago
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Match each element to the number of electrons in its valence shell
blondinia [14]

Answer: Be= 2, C =4,  Li = 1 and  B=3

Explanation:

The valence shell can be define as the outermost shell of an atom that contains the valence electrons.

Beryllium (Be), electronic configuration; 1s2 2s2, = 2 electrons in its valence shell.

Carbon (C), electronic configuration; 1s2 2s2 2p2, = 4 electrons in its valence shell.

Lithium (Li), electronic configuration; 1s2 2s1 = 1 electron in its valence shell.

Boron (B) , electronic configuration; 1s2 2s2 2p1 = 3 electron in its valence shell.

6 0
3 years ago
Name Formula: Lead (II) Oxide<br> F) Pb2O<br><br> G) PbO2<br><br> H) PbO<br><br> I) Pb2O2
garik1379 [7]

Answer:

PbO is the Answer

Explanation:

4 0
3 years ago
Pressure gauge at the top of a vertical oil well registers 140 bars. The oil well is 6000 m deep and filled with natural gas dow
andreyandreev [35.5K]

Explanation:

(a)  The given data is as follows.

              Pressure on top (P_{o}) = 140 bar = 1.4 \times 10^{7} Pa       (as 1 bar = 10^{5})

              Temperature = 15^{o}C = (15 + 273) K = 288 K

         Density of gas = \frac{PM}{ZRT}

                \frac{dP}{dZ} = \rho \times g

               \frac{dP}{dZ} = \int \frac{PM}{ZRT}

                \int_{P_{o}}^{P_{1}} \frac{dP}{dZ} = \frac{Mg}{ZRT} \int_{0}^{4700} dZ

           ln (\frac{P_{1}}{P_{o}}) = \frac{18.9 \times 10^{-3} \times 9.81 \times 4700 m}{0.80 \times 8.314 J/mol K \times 288 K}

                              = 0.4548

                     P_{1} = P_{o} \times e^{0.4548}

                                 = 1.4 \times 10^{7} Pa \times 1.5797

                                 = 2.206 \times 10^{7} Pa

Hence, pressure at the natural gas-oil interface is 2.206 \times 10^{7} Pa.

(b)   At the bottom of the tank,

                 P_{2} = P_{1}  + \rho \times g \times h

                             = 2.206 \times 10^{7} Pa + 700 \times 9.81 \times (6000 - 4700)[/tex]

                             = 309.8 \times 10^{5} Pa

                             = 309.8 bar

Hence, at the bottom of the well at 15^{o}C pressure is 309.8 bar.

6 0
3 years ago
14. What is a major disadvantage of using solar power?
sleet_krkn [62]
I believe that number 27 is A
8 0
3 years ago
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