The density of a 15.00% by mass aqueous solution of acetic acid, CH3COOH, is 1.0187g/mL. What is (a) the molarity? (b) the molal
ity? (c) the mole fraction of each component?
1 answer:
<span>What is (a) the molarity?
.15 g CH3COOH / g solution ( 1 mol / 60.05 g ) (1018.7 g / L ) = 2.5 mol / L or 2.05 M
(b) the molality?
</span>.15 g CH3COOH / g solution ( 1 mol / 60.05 g ) ( 1000 g / 1kg ) = 2.5 mol/kg or 2.5 m<span>
Hope this helped. Have a nice day.
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