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2 years ago

How many sodium atoms does 3Na2S2O3 have?

Chemistry

1 answer:

zhuklara [117]2 years ago

4 0

Answer:

Element, Symbol, Atomic Mass, # of Atoms, Mass Percent. Sodium, Na, 137.9386 g/mol, 6, 29.0811%. Sulphur/Sulfur, S, 192.39 g/mol, 6, 40.5609%Explanation:

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What is the formula for P₃O₅?

marshall27 [118]

Answer:

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Explanation:

and goodnight,goodevening,goodmorning

6 0

3 years ago

Given a fixed amount of gas in a rigid container (no change in volume), what pressure will the gas exert if the pressure is init

Masja [62]

Answer:

The pressure the gas will have if the pressure is initially 1.50 atm at 22.0 ° C and the temperature changes at 11.0 ° C is 1.44 atm (option D)

Explanation:

Gay Lussac's law indicates that, as long as the volume of the container containing the gas is constant, as the temperature increases, the gas molecules move more rapidly. Then the number of collisions against the walls increases, that is, the pressure increases. That is, the gas pressure is directly proportional to its temperature.

Gay-Lussac's law can be expressed mathematically as follows:

$\frac{P}{T}=k$

Where P = pressure, T = temperature, K = Constant

You have a gas that is at a pressure P1 and at a temperature T1. When the temperature varies to a new T2 value, then the pressure will change to P2, and then:

$\frac{P1}{T1}=\frac{P2}{T2}$

In this case:

P1= 1.50 atm
T1= 22 °C= 295 °K (being 0°C= 273 °K)
P2= ?
T2= 11 °C= 284 K

Replacing:

$\frac{1.5 atm}{295 K}=\frac{P2}{284 K}$

Solving:

$P2= 284 K*\frac{1.5 atm}{295 K}$

P2=1.44 atm

The pressure the gas will have if the pressure is initially 1.50 atm at 22.0 ° C and the temperature changes at 11.0 ° C is 1.44 atm (option D)

8 0

3 years ago

Balancing Equations help (please explain)

klemol [59]

Answer:

A balanced equation is an equation for a chemical reaction in which the number of atoms for each element in the reaction and the total charge is the same for both the reactants and the products. In other words, the mass and the charge are balanced on both sides of the reaction.

Explanation:

8 0

3 years ago

An aqueous solution containing 10 g of an optically pure compound was diluted to 500 mL with water and was found to have a speci

lapo4ka [179]

Answer:

Optical purity = 76.9231 %

Specific rotation of mixture = - 97.6923 °

Explanation:

The mass of the racemic mixture = 3 g

It means it contains R enantiomer = 1.5 g

S enantiomer = 1.5 g

Amount of Pure R = 10 g

Total R = 11.5 g

Total volume = 500 mL + 500 mL = 1000 mL = 1 L

[R] = 11.5 g/L

[S] = 1.5 g/L

Enantiomeric excess = $\frac {Excess}{Total\ Concentration}\times 100$ = $\frac {11.5-1.5}{11.5+1.5}\times 100$ = 76.9231 %

Optical purity = 76.9231 %

Also,

Optical purity = $\frac {optical\ rotation\ of\ mixture}{optical\ rotation\ of\ pure\ enantiomer}\times 100$

Optical rotation of pure enantiomer = −127 °

$76.9231=\frac {optical\ rotation\ of\ mixture}{-127^0}\times 100$

Specific rotation of mixture = - 97.6923 °

6 0

3 years ago

Which of the five type of equilibrium problems best applies to this question: Consider the following reaction at equilibrium. Wh

andreev551 [17]

Answer:

Explanation:

3 0

3 years ago