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AysviL [449]
2 years ago
12

How many sodium atoms does 3Na2S2O3 have?

Chemistry
1 answer:
zhuklara [117]2 years ago
4 0

Answer:

Element, Symbol, Atomic Mass, # of Atoms, Mass Percent. Sodium, Na, 137.9386 g/mol, 6, 29.0811%. Sulphur/Sulfur, S, 192.39 g/mol, 6, 40.5609%Explanation:

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The term Reuther Ford gave to the positively charged particles in the nucleus of an antom was
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The term Rutherford gave to the positively charged particles in the nucleus of an atom was/is Proton. 

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4 0
3 years ago
Which results when an atom has such a strong attraction for electrons that it pulls one or more electrons completely away from a
IgorLugansk [536]

<em><u>All people are tax people</u></em>

-Turbo tax

4 0
3 years ago
If a reaction occurs, what will be the products of the unbalanced reaction below?
castortr0y [4]

Explanation:

I think the correct answer is B

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8 0
3 years ago
Be sure to answer all parts. Consider the reaction A + B → Products From the following data obtained at a certain temperature, d
worty [1.4K]

Answer : The order of reaction with respect to A is, first order reaction.

The order of reaction with respect to B is, zero order reaction.

The overall order of reaction is, first order reaction.  

Explanation :

Rate law is defined as the expression which expresses the rate of the reaction in terms of molar concentration of the reactants with each term raised to the power their stoichiometric coefficient of that reactant in the balanced chemical equation.

For the given chemical equation:

A+B\rightarrow Products

Rate law expression for the reaction:

\text{Rate}=k[A]^a[B]^b

where,

a = order with respect to A

b = order with respect to B

Expression for rate law for first observation:

3.20\times 10^{-1}=k(1.50)^a(1.50)^b ....(1)

Expression for rate law for second observation:

3.20\times 10^{-1}=k(1.50)^a(2.50)^b ....(2)

Expression for rate law for third observation:

6.40\times 10^{-1}=k(3.00)^a(1.50)^b ....(3)

Dividing 1 from 2, we get:

\frac{3.20\times 10^{-1}}{3.20\times 10^{-1}}=\frac{k(1.50)^a(2.50)^b}{k(1.50)^a(1.50)^b}\\\\1=1.66^b\\b=0

Dividing 1 from 3, we get:

\frac{6.40\times 10^{-1}}{3.20\times 10^{-1}}=\frac{k(3.00)^a(1.50)^b}{k(1.50)^a(1.50)^b}\\\\2=2^a\\a=1

Thus, the rate law becomes:

\text{Rate}=k[A]^1[B]^0

\text{Rate}=k[A]

Thus,

The order of reaction with respect to A is, first order reaction.

The order of reaction with respect to B is, zero order reaction.

The overall order of reaction is, first order reaction.

7 0
3 years ago
3. A 0.025L solution of HCl is neutralized by 0.018L of a 1.0 M NaOH solution. What is the concentration of the HCl solution?​
Nookie1986 [14]

The concentration of the HCl solution is 0.72 M.

<h3>How do we calculate the concentration?</h3>

Concentration of the required solution by the use of the known concentration solution will be determine by using the below equation as:

M₁V₁ = M₂V₂, where

  • M₁ & V₁ are the molarity and volume of the HCl solution.
  • M₂ & V₂ are the molarity and volume of the NaOH solution.

On putting values in the above equation, we get

M₁ = (1)(0.018) / (0.025) = 0.72 M

Hence required concentration of HCl is 0.72M.

To know kore about molarity, visit the below link:

brainly.com/question/24305514

#SPJ1

4 0
2 years ago
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