Answer: The final temperature of both substances at thermal equilibrium is 301.0 K
Explanation:

As we know that,

.................(1)
where,
q = heat absorbed or released
= mass of gold = 31.5 g
= mass of water = 63.4 g
= final temperature = ?
= temperature of gold = 
= temperature of water = 
= specific heat of gold = 
= specific heat of water= 
Now put all the given values in equation (1), we get
![-31.5\times 0.129\times (T_{final}-342.4)=[63.4\times 4.184\times (T_{final}-300.4)]](https://tex.z-dn.net/?f=-31.5%5Ctimes%200.129%5Ctimes%20%28T_%7Bfinal%7D-342.4%29%3D%5B63.4%5Ctimes%204.184%5Ctimes%20%28T_%7Bfinal%7D-300.4%29%5D)

The final temperature of both substances at thermal equilibrium is 301.0 K
Answer: Okay so here's the order lol from top to bottom
2, 1, 3, 4, 5
Explanation:
It would be d.
Reason being said...
the electron configuration normally goes like this...
1s2 2s2 2p6 3s2 3p6 4s2....
until you hit the transition metals..remember those have a special rule..
even though you are in the 4 sublevels for the orbitals ... it goes down 1
Making it 3d..(1,2,3,4,5,6,7,8,9,10)
Going on...
at 5s2 then, 4d1, 4d2, 4d3, 4d4, etc..
at 6s2 then, 5d1, 6d2, 6d3, 6d4, etc..
Thus, D orbital is your answer.
Answer:
kJ/mol
Explanation:
Given and known facts
Mass of Benzene
grams
Mass of water
grams
Standard heat capacity of water
J/g∙°C
Change in temperature ΔT
°C
Heat

Heat released by benzine is - 7.82 kJ
Now, we know that
grams of benzene release
kJ heat
So,
g benzine releases

kJ/g
mol C6H6
Heat released

kJ/mol