Answer:
The answer to your question is 8.74 g of He
Explanation:
Data
V = 2.4 x 10² L
P = 99 kPa
T = 0°C
mass = ?
Process
1.- Convert kPa to atm
P = 99 kPa = 99000 Pa
1 atm --------------- 101325 Pa
x --------------- 99000 Pa
x = (99000 x 1) / 101325
x = 0.977 atm
2.- Convert temperature to °K
°K = 273 + 0
°K = 273
3.- Substitution
PV = nRT
- Solve for n
n = PV / RT
n = (0.977)(2.4 x 10²) / (0.082)(273)
n = 24.48 / 22.386
n = 1.093 moles
4.- Calculate the grams of He
8 g -------------------- 1 mol
x -------------------- 1.093 moles
x = (1.093 x 8) / 1
x = 8.74 g
<span>Since chlorine favours a (-1) oxidation state, it forms an ionic bond with group one metals with the formula XCl. All group one metals react vigorously with chlorine gas; and each reaction gets more violent as you move down Group 1 and produces a white crystalline salt. The reaction with chlorine is as follows 2X + Cl2 which gives 2XCl. Where X is an Alkali metal.</span>
Covalent since they are both non metals, a metal and a non metal make an ionic bond
Mass:20g
Mole=20/[2(23)+16]
=0.32 mil