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djyliett [7]
2 years ago
7

Why does the lithium atom develop a positive charge?​

Chemistry
1 answer:
Anuta_ua [19.1K]2 years ago
7 0

Answer:

A lithium atom has 3 protons and 3 electrons. It can lose one of its electrons, making it an ion. It now has more positive protons than electrons so it has an overall positive charge. Therefore it is a positive ion.

Explanation:

Lithium, an alkali metal with three electrons, is also an exception to the octet rule. Lithium tends to lose one electron to take on the electron configuration of the nearest noble gas, helium, leaving it with two valence electrons.

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In the following reaction, eight moles of sodium hydroxide is broken down into four moles of sodium oxide and four moles of wate
maxonik [38]

Answer:

21.344%

Explanation:

For the given chemical reaction, 8 moles of the reactant should produce 4 moles of Na_{2}O. However, 195 g of Na_{2}O was produced instead. The molar mass of Na_{2}O is 61.9789 g/mol.

Thus, the moles of Na_{2}O produced = 195/61.9789 = 3.1462 moles

The percent error = [(Actual -Experiment)/Actual]*100%

The percent error =  [(4.00 - 3.1462)/4.00]*100% = (0.85376/4.00)*100% = 21.344%

8 0
4 years ago
#12, how do I solve this
Likurg_2 [28]
Find the molar mass of the compound, then get the unit cancel out until u reach "g"

5 0
3 years ago
Assume that 300 J of heat is added to 3.00g of water originally at 23°C. what would be the final temperature of the water?  The
Iteru [2.4K]

Answer:

47C

Explanation:

Recall the equation for specific heat:

q = mcΔT

300 = 3 x 4.184 x (T - 23)

T = 47

3 0
3 years ago
exactly 1mol of n2o4 is placed in an empty 1 l container. if at equilibrium n2o4 is dissociated 20%, what is the value of equili
egoroff_w [7]

Answer:

K = 0.2

Explanation:

Based on the chemical dissociation of N₂O₄:

N₂O₄ ⇄ 2NO₂

The equilibrium constant, K, of the reaction is:

K = [NO₂]² / [N₂O₄]

Now, if 20% of N₂O₄ is dissociated, 80% remains as N₂O₄ = 0.8mol/L = 0.8M

as 20% is dissociated, 0.2moles of N₂O₄ were dissociated and 0.2*2 = 0.4mol/L of NO₂ are produced.

Replacing in K:

K = [0.4M]² / [0.8M]

<h3>K = 0.2</h3>
5 0
3 years ago
What is the length (in cm) of the side of an iron ingot (rectangular box) that has a mass of 4.578 kg and has width = height = 5
AfilCa [17]
Since we have the mass of the iron ingot we can get its volume by dividing the mass (4.578) by the density of iron (7874 kgm^-3) and we get that the volume is 5.8140716x10^-4 m^3. now we convert the volume from m^3 to cm^3(1m^3=1000000cm^3) and so by multiplying  5.8140716x10^-4 by <span>1000000 we get:581.4cm^3 (1 decimal place).

the volume for any  cuboid is V=l x w x s we have the volume, the length and the  width, so we plug in the values and solve for s
</span>s= \frac{581.4}{5^{2} } =23.3cm
 the answer is rounded to three significant figures

hope i helped
5 0
4 years ago
Read 2 more answers
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