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2 years ago

6

Use the expression (10p+10)+(8p−1). Simplify using properties of operations and then factor the expression using the GCF.

1 answer:

Fofino [41]2 years ago

7 0

Answer:

9 (2p + 1)

Step-by-step explanation:

(18p + 9)

GCF = 9

so, divide everything by 9

9 (2p + 1)

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Two functions are graphed on the coordinate plane.

rosijanka [135]

Answer:

Option B

Step-by-step explanation:

We can see that, from the picture provided, the graphs intersect at points( 0, 4 ) and ( - 4, 4 ), respective to functions f( x ) and g( x ). These intersection points makes each function equivalent to one another, and hence -

Function f( x ) where x = - 4 / Function g( x ) where x = - 4,

$f( - 4 ) = 4,\\g( - 4 ) = 4\\----------\\f ( - 4 ) = g ( - 4 )$

Respectively function f( x ) where x = 0 / Function g( x ) where x = 0,

$f( 0 ) = 4,\\g( 0 ) = 4\\----------\\f ( 0 ) = g ( 0 )$

<u><em>Your solution should be option b, " f(-4) = g(-4) and f(0) = g(0) "</em></u>

7 0

2 years ago

In her sixth-grade social studies class, Mrs. Davis has 22 students, 12 of whom are girls. If one

tatiyna

Answer:

5/11

Step-by-step explanation:

Please let me know if you want me to add an explanation as to why this is the answer. I can definitely do that, I just wouldn’t want to write it if you don’t want me to :)

8 0

2 years ago

Read 2 more answers

(33) Please check my answer in geo thanks<br><br> I am not 100% about this one

Reil [10]

Yes this is using the transitive property
Point A leads to point B, B goes to C, so overall A goes to C. Think of it connecting a chain.

Nice job on getting the correct answer.

5 0

3 years ago

Linda had 84 fliers to post around town. Last week, she posted 1/3 of them. This week, she posted 2/7 of the remaining fliers. H

Jobisdone [24]

The remaining number of flires that Linda still not posted is 40.

According to the given question.

The total number of fliers Linda have = 84

Fraction of fliers Linda posted = 1/3

And, fraction of fliers Linda posted second time from the remaning fliers = 2/7

Now,

1/3 of 84 fliers = 1/3 × 84 = 28

So, the number of fliers are left with Linda after first posting = 84 - 28 = 56

Again she posted 2/7 fliers. The number of flires Linda posted second time is given by

⇒ 2/7 × 56 = 16

Thereore, the number of fliers that Lindna still not posted = 56 - 16 = 40

Hence, Linda still not posted 40 fliers.

Find out more information about fraction and remaining numbers here:

brainly.com/question/2254581

#SPJ4

4 0

1 year ago

Can someone help me with this please? I will mark you brainliest

lina2011 [118]

Answer:

On the vertical axis, place frequencies. Label this axis "Frequency".

On the horizontal axis, place the lower value of each interval. ...

Draw a bar extending from the lower value of each interval to the lower value of the next interval.On the vertical axis, place frequencies. Label this axis "Frequency".

On the horizontal axis, place the lower value of each interval. ...

Draw a bar extending from the lower value of each interval to the lower value of the next interval.On the vertical axis, place frequencies. Label this axis "Frequency".

On the horizontal axis, place the lower value of each interval. ...

Draw a bar extending from the lower value of each interval to the lower value of the next interval.On the vertical axis, place frequencies. Label this axis "Frequency".

On the horizontal axis, place the lower value of each interval. ...

Draw a bar extending from the lower value of each interval to the lower value of the next interval.On the vertical axis, place frequencies. Label this axis "Frequency".

On the horizontal axis, place the lower value of each interval. ...

Draw a bar extending from the lower value of each interval to the lower value of the next interval.On the vertical axis, place frequencies. Label this axis "Frequency".

On the horizontal axis, place the lower value of each interval. ...

Draw a bar extending from the lower value of each interval to the lower value of the next interval.On the vertical axis, place frequencies. Label this axis "Frequency".

On the horizontal axis, place the lower value of each interval. ...

Draw a bar extending from the lower value of each interval to the lower value of the next interval.On the vertical axis, place frequencies. Label this axis "Frequency".

On the horizontal axis, place the lower value of each interval. ...

Draw a bar extending from the lower value of each interval to the lower value of the next interval.On the vertical axis, place frequencies. Label this axis "Frequency".

On the horizontal axis, place the lower value of each interval. ...

Draw a bar extending from the lower value of each interval to the lower value of the next interval.On the vertical axis, place frequencies. Label this axis "Frequency".

On the horizontal axis, place the lower value of each interval. ...

Draw a bar extending from the lower value of each interval to the lower value of the next interval.On the vertical axis, place frequencies. Label this axis "Frequency".

On the horizontal axis, place the lower value of each interval. ...

Draw a bar extending from the lower value of each interval to the lower value of the next interval.On the vertical axis, place frequencies. Label this axis "Frequency".

On the horizontal axis, place the lower value of each interval. ...

Draw a bar extending from the lower value of each interval to the lower value of the next interval.On the vertical axis, place frequencies. Label this axis "Frequency".

On the horizontal axis, place the lower value of each interval. ...

Draw a bar extending from the lower value of each interval to the lower value of the next interval.On the vertical axis, place frequencies. Label this axis "Frequency".

On the horizontal axis, place the lower value of each interval. ...

Draw a bar extending from the lower value of each interval to the lower value of the next interval.vvOn the vertical axis, place frequencies. Label this axis "Frequency".

On the horizontal axis, place the lower value of each interval. ...

Draw a bar extending from the lower value of each interval to the lower value of the next interval.vcOn the vertical axis, place frequencies. Label this axis "Frequency".

On the horizontal axis, place the lower value of each interval. ...

Draw a bar extending from the lower value of each interval to the lower value of the next interval.On the vertical axis, place frequencies. Label this axis "Frequency".

On the horizontal axis, place the lower value of each interval. ...

Draw a bar extending from the lower value of each interval to the lower value of the next interval.On the vertical axis, place frequencies. Label this axis "Frequency".

On the horizontal axis, place the lower value of each interval. ...

Draw a bar extending from the lower value of each interval to the lower value of the next interval.

Step-by-step explanation:

6 0

3 years ago