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2 years ago

Solve the equation by finding the common denominator. two and four sevenths plus seven and three ninths equals blank

Mathematics

1 answer:

kotegsom [21]2 years ago

7 0

Answer:

9 19/21

Step-by-step explanation:

2 and 4/7 + 7 3/9 or 7 1/3. If you find common denominator its 21. So 2 and 12/21 and 7 7/21. If you add that would equal 9 19/21.

Hope this helps :)

You might be interested in

Find the area of the larger sector.

Wewaii [24]

Step-by-step explanation:

the formula for the area of a sector is

(x°(r^2)π)/360

with x being the angle

r bring the radius of the circle

(255(13.4)^2π)/360

399.6

Hope that helps :)

3 0

3 years ago

The mayor is interested in finding a 98% confidence interval for the mean number of pounds of trash per person per week that is

saul85 [17]

Solution :

Given :

Sample mean, $\overline X = 34.2$

Sample size, n = 129

Sample standard deviation, s = 8.2

a. Since the population standard deviation is unknown, therefore, we use the t-distribution.

b. Now for 95% confidence level,

α = 0.05, α/2 = 0.025

From the t tables, T.INV.2T(α, degree of freedom), we find the t value as

t =T.INV.2T(0.05, 128) = 2.34

Taking the positive value of t, we get

Confidence interval is ,

$\overline X \pm t \times \frac{s}{\sqrt n}$

$34.2 \pm 2.34 \times \frac{8.2}{\sqrt {129}}$

(32.52, 35.8)

95% confidence interval is (32.52, 35.8)

So with $95 \%$ confidence of the population of the mean number of the pounds per person per week is between 32.52 pounds and 35.8 pounds.

c. About $95 \%$ of confidence intervals which contains the true population of mean number of the pounds of the trash that is generated per person per week and about $5 \%$ that doe not contain the true population of mean number of the pounds of trashes generated by per person per week.

4 0

2 years ago

Two problems here I need solved! I need every step, so please have that with your answers!!

Free_Kalibri [48]

QUESTION 1

We want to solve,

$\frac{1}{(x-4)}+\frac{x}{(x-2)}=\frac{2}{x^{2}-6x+8}$

We factor the denominator of the fraction on the right hand side to get,

$\frac{1}{(x-4)}+\frac{x}{(x-2)}=\frac{2}{x^{2}-4x - 2x+8}.$

This implies
$\frac{1}{(x-4)}+\frac{x}{(x-2)}=\frac{2}{x(x-4) - 2(x - 4)}.$

$\frac{1}{(x-4)}+\frac{x}{(x-2)}=\frac{2}{(x-4)(x - 2)}$

We multiply through by LCM of
$(x-4)(x - 2)$

$(x - 2) + x(x-4) = 2$

We expand to get,

$x - 2 + {x}^{2} - 4x= 2$

We group like terms and equate everything to zero,

${x}^{2} + x - 4x - 2 - 2 = 0$

We split the middle term,

${x}^{2} + - 3x - 4 = 0$

We factor to get,

${x}^{2} + x - 4x- 4 = 0$

$x(x + 1) - 4(x + 1) = 0$

$(x + 1)(x - 4) = 0$

$x + 1 = 0 \: or \: x - 4 = 0$

$x = - 1 \: or \: x = 4$

But
$x = 4$
is not in the domain of the given equation.

It is an extraneous solution.

$\therefore \: x = - 1$
is the only solution.

QUESTION 2

$\sqrt{x+11} -x=-1$

We add x to both sides,

$\sqrt{x+11} =x-1$

We square both sides,

$x + 11 = (x - 1)^{2}$

We expand to get,

$x + 11 = {x}^{2} - 2x + 1$

This implies,

${x}^{2} - 3x - 10 = 0$

We solve this quadratic equation by factorization,

${x}^{2} - 5x + 2x - 10 = 0$

$x(x - 5) + 2(x - 5) = 0$

$(x + 2)(x - 5) = 0$

$x + 2 = 0 \: or \: x - 5 = 0$

$x = - 2 \: or \: x = 5$

But
$x = - 2$
is an extraneous solution

$\therefore \: x = 5$

7 0

3 years ago

HELP^^ LOOK AT THE PICTURE. this is algebra in & out tables ?

s2008m [1.1K]

Answer:

a= 1 , b = 1/16 , c = 1/256 , d= 3/2 , e=4/9 , f= 16/81

Step-by-step explanation:

The first table is given as;

x 4⁻ˣ

-1 4

0 1

2 1/16

4 1/256

a= 1 , b = 1/16 , c = 1/256

The second table is given as;

x {2/3}^x

-1 3/2

0 1

2 4/9

4 16/81

d= 3/2 , e=4/9 , f= 16/81

5 0

3 years ago

HELP!!

earnstyle [38]

12 times 2 is 24, and 24 times 2 is 48, so there was 48 cookies

6 0

3 years ago