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3 years ago

The frequency of a microwave signal is 9.76 ghz. what is its wavelength? (c = 3.00 × 108 m/s)

1 answer:

8 0

The basic relationship between frequency of an electromagnetic wave and wavelength of the wave is
$c = \lambda f$
where $c=3 \cdot 10^8 m/s$ is the speed of light.

Manipulating the equation, we can rewrite it as
$\lambda = \frac{c}{f}$

The frequency of the wave in our problem is
$9.76 GHz = 9.76 \cdot 10^9 Hz$
so if we use the previous formula, we find the correspondant wavelength:
$\lambda = \frac{3 \cdot 10^8 m/s}{9.76 \cdot 10^9 Hz} =0.031 m$

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Explanation:

It is given that,

Initial vapor pressure, P₁ = 77.86 mm

Initial temperature, T₁ = 318.3 K

Final vapor pressure, P₂ = 161.3 mm

Initial temperature, T₂ = 340.7 K

We need to find its heat of vaporization. It can be calculated by using Clausius-Clapeyron equation.

$ln(\dfrac{P_2}{P_1})=\dfrac{\Delta_{vap}H}{R}(\dfrac{1}{T_1}-\dfrac{1}{T_2})$

$\Delta _{vap} H=\dfrac{R\ ln(\dfrac{P_2}{P_1})}{(\dfrac{1}{T_1}-\dfrac{1}{T_2})}$

$\Delta _{vap} H=\dfrac{0.008 314\ ln(\dfrac{161.3}{77.86})}{(\dfrac{1}{318.3}-\dfrac{1}{340.7})}$

$\Delta _{vap} H=29.31\ kJ/mol$

So, the heat of vaporization of a substance is 29.31 kJ/mol. Hence, this is the required solution.

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3 years ago

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Answer:

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BECAUSE

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Answer:

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Explanation:

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