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3 years ago

The frequency of a microwave signal is 9.76 ghz. what is its wavelength? (c = 3.00 × 108 m/s)

1 answer:

8 0

The basic relationship between frequency of an electromagnetic wave and wavelength of the wave is
$c = \lambda f$
where $c=3 \cdot 10^8 m/s$ is the speed of light.

Manipulating the equation, we can rewrite it as
$\lambda = \frac{c}{f}$

The frequency of the wave in our problem is
$9.76 GHz = 9.76 \cdot 10^9 Hz$
so if we use the previous formula, we find the correspondant wavelength:
$\lambda = \frac{3 \cdot 10^8 m/s}{9.76 \cdot 10^9 Hz} =0.031 m$

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$T = \frac{ Id^{2}\theta }{dt^{2} }$

$-\mu B\theta=\frac{ Id^{2}\theta }{dt^{2} }$

$\frac{d^{2}\theta }{dt^{2} } = -(\frac{\mu BI}{\theta} )$

By Comparing the above equation with the SHM equation

$\frac{d^2 \theta} {dt^{2} } = -\omega^{2} \theta$

$\omega^{2} =\frac{ \mu B}{I}$

Frequency = $\frac{\mu}{2\pi }$

= $\frac{\sqrt{\frac{\mu B}{I} } }{2\pi}$

= $\frac{1}{2\pi } \sqrt{\frac{\mu B}{I} }$

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1 year ago

A. 7cm<br>B. 24cm<br>C. 18cm<br>D. 63cm

Alex17521 [72]

Answer:

A. 7cm

I hope it helps...

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3 years ago

6. The first vertebrates appeared during

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Answer:

b. the Paleozoic Era

Explanation:

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2 years ago

Scientists earlier believed that the lowest measurable temperature is the freezing point of ice. However, modern scientists beli

djverab [1.8K]

I think the correct answer from the choices listed above is the first option. The statement that best accounts for these different opinions would be that <span>scientists propose contradictory ideas to include all possibilities. Hope this answers the question. Have a nice day.</span>

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3 years ago

Read 2 more answers

Suppose a convex mirror has a focal length of 120 cm. A candle sits directly in front of the mirror. If the image of that candle

Andru [333]

We can solve the problem by using the mirror equation:
$\frac{1}{f} = \frac{1}{d_o}+ \frac{1}{d_i}$
where
f is the focal length
$d_o$ is the distance of the object from the mirror
$d_i$ is the distance of the image from the mirror

For the sign convention, the focal length is taken as negative for a convex mirror:
$f=-120 cm$
and the image is behind the mirror, so virtual, therefore its sign is negative as well:
$d_i=-24 cm$
putting the numbers in the mirror equation, we find the distance of the object from the mirror surface:
$\frac{1}{d_o} = \frac{1}{f}- \frac{1}{d_i}= \frac{1}{-120 cm} - \frac{1}{-24 cm}= \frac{1}{30 cm}$
So, the distance of the object from the mirror is $d_o = 30 cm$

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3 years ago