Answer is 3 seconds
When the bullet reaches the ground, ground being x in graph (and here its s which is = 0)
s = -16t^2 + 48t
s = 0, solve for t
0 = -16t^2 + 48t
0 = t ( -16t + 48)
0 = 16t ( - t + 3)
now you have two equation
0 = 16t and 0 = -t +3 ( you can look at the graph line touches x twice)
0 = 16 t
0 = t ( you know its false, because time = 0)
You are left with
0 = -t + 3
t = 3
It takes 3 seconds for the bullet to return to the ground.
// Hope this helps.
Answer:
The coordinates of B' and C' are and
, respectively.
Step-by-step explanation:
From the Linear Algebra, we define the translation of a given point as:
(1)
Where:
- Original point, dimensionless.
- Translation vector, dimensionless.
- Translated point, dimensionless.
If we know that and
, then the translation vector is:
(2)
If we know that ,
and
, then the translated points are, respectively:
(3)
The coordinates of B' and C' are and
, respectively.