Question

Segment PE has endpoints P(-4,4) and E(0,-4). Find the coordinates of point Q such that PQ:QE is 1:3. Enter the coordinates below

Answer 1

Answer:

(-3, 2)

Step-by-step explanation:

Given that point Q, partitions segment PE, such that PQ:QE is 1:3, coordinates of point Q is found using the formula below:

$x = \frac{mx_2 + nx_1}{m + n}$

$y = \frac{my_2 + ny_1}{m + n}$

Where,

$P(-4, 4) = (x_1, y_1)$

$E(0, -4) = (x_2, y_2)$

$m = 1, n = 3$

Plug in the necessary values to find x and y coordinates for point Q as follows:

$x = \frac{mx_2 + nx_1}{m + n}$

$x = \frac{1(0) + 3(-4)}{1 + 3}$

$x = \frac{0 - 12}{4}$

$x = \frac{-12}{4}$

$x = -3$

$y = \frac{my_2 + ny_1}{m + n}$

$y = \frac{1(-4) + 3(4)}{1 + 3}$

$y = \frac{-4 + 12}{4}$

$y = \frac{8}{4}$

$y = 2$

The coordinates of the point Q are (-3, 2))