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3 years ago

Please people help WHAT IS THE ANSWER? NO LINKS PLEASE

Chemistry

2 answers:

erastovalidia [21]3 years ago

6 0

Answer:

d i think sorry if im worng

Explanation:

Lyrx [107]3 years ago

4 0

The answer is A, the texture

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Hi! It would be awesome if you could answer this soon. 20 points!

NikAS [45]

Answer:

2HgO → 2Hg + O₂

The reaction is a decomposition reaction because from one reactant two products were obtained

Explanation:

The problem here involves balancing the chemical reaction given and also classifying the reaction.

The unbalanced expression is given as:

HgO → Hg + O₂

Assign the alphabets a,b and c as coefficients that will balance the equation

aHgO → bHg + cO₂

Conserving Hg: a = b

O: a = 2c

So, let c = 1, a = 2 b = 2

Therefore;

2HgO → 2Hg + O₂

The reaction is a decomposition reaction because from one reactant two products were obtained

3 0

3 years ago

The density of acetonitrile (CH3CN) is 0.786 g/mL, and the density of methanol (CH3OH) is 0.791 g/mL. A solution is made by diss

ololo11 [35]

Answer:

The answer to your question is 0.22

Explanation:

Data

Acetonitrile (CH₃CN) density = 0.786 g/ml

Methanol (CH₃OH) density = 0.791 g/ml

Volume of CH₃OH = 22 ml

Volume of CH₃CN = 98.4 ml

Process

1.- Calculate the mass of Acetonitrile and the mass of Methanol

density = mass/ volume

mass = density x volume

Acetonitrile

mass = 0.786 x 98.4

= 77.34 g

Methanol

mass = 0.791 x 22

= 17.40 g

2.- Calculate the moles of the reactants

Acetonitrile molar mass = (12 x 2) + (14 x 1) + (3 x 1)

= 24 + 14 + 3

= 41 g

Methanol molar mass = (12 x 1) + (4 x 1) + (16 x 1)

= 12 + 4 + 16

= 32 g

Moles of Acetonitrile

41 g ----------------- 1 mol

77.34g ------------ x

x = (77.34 x 1) / 41

x = 1.89 moles

Moles of Methanol

32 g -------------- 1 mol

17.40 g --------- x

x = (17.40 x 1)/32

x = 0.54 moles

3.- Calculate the mole fraction of Methanol

Total number of moles = 1.89 + 0.54

= 2.43

Mole fraction = moles of Methanol / total number of moles

Mole fraction = 0.54/ 2.43

Mole fraction = 0.22

6 0

4 years ago

Number of stable isotopes in Hydrogen?

kari74 [83]

3.
protium (A = 1), deuterium (A = 2), and tritium (A = 3).

5 0

3 years ago

Read 2 more answers

a sample of gas initially occupies 5.50 liter at a pressure of 0.750 atm at 13.0 C. what will the temperture change to 22.5 C an

sergey [27]

Answer:

The pressure will be 2.84 atm

Explanation:

The gas laws are a set of chemical and physical laws that allow us to determine the behavior of gases in a closed system. The parameters evaluated in these laws are pressure, volume, temperature and moles.

Boyle's law indicates that the volume is inversely proportional to the pressure: if the pressure increases, the volume decreases and if the pressure decreases, the volume increases. Boyle's law is expressed mathematically as:

P * V = k

On the other hand, Charles's law indicates that with increasing temperature, the volume of the gas increases and with decreasing temperature, the volume of the gas decreases. That is, they are directly proportional. This is expressed mathematically as:

$\frac{V}{T} =k$

Finally, the Gay-Lussac law says that at constant volume, the pressure of the gas is directly proportional to its temperature. Mathematically, it is expressed as:

$\frac{P}{T} =k$

Combined law equation is the combination of three gas laws called Boyle's, Charlie's and Gay-Lusac's law:

$\frac{P*V}{T}=k$

When you want to study two different states, an initial and a final one of a gas, you can use the following expression:

$\frac{P1*V1}{T1}=\frac{P2*V2}{T2}$

In this case:

P1= 0.750 atm
V1= 5.50 L
T1= 13 C= 286 K (being 0 C=273 K)
P2=?
V2= 1.50 L
T2= 22.5 C=295.5 K

Replacing:

$\frac{0.750 atm*5.50 L}{286 K}= \frac{P2*1.50 L}{295.5 K}$

Solving:

$P2=\frac{295.5K}{1.50L} *\frac{0.750 atm*5.50 L}{286 K}$

P2= 2.84 atm

<u><em>The pressure will be 2.84 atm</em></u>

8 0

4 years ago

If a non-cyclic alkane shows a molecular ion peak at m/z 3.80 × 102, what is the chemical formula?

soldier1979 [14.2K]

The General Equation of Alkane is as follow,

CnH₂n₊₂ ------- (1)
As m/z = 380
So,
CnH₂n₊₂ = 380
Or,
12n+ 1₂n₊₂ = 380

12n+ ₂n ₊ ₂ = 380

14n ₊ ₂ = 380

14n = 380 - 2

14n = 378

n = 378 / 14

n = 27
Now, putting value of n in eq. 1

C₂₇H₍₂₇ₓ₂₎₊₂

C₂₇H₅₆
Result:
n = C = 27

y = H = 56

4 0

4 years ago