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4 years ago

Which of the following are properties of mechanical waves?

Chemistry

1 answer:

swat324 years ago

3 0

Answer:

A mechanical wave can be described as a wave that moves by oscillations and transfers energy in a medium.

Some of the properties of the mechanical waves are:

1) The frequency of a wave equals the frequency of the vibrating source which is producing the wave.

2) Increasing the frequency of a wave decreases its wavelength.

3) The speed of a wave is equal to the wavelength multiplied by frequency.

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4.80 x 10^25 formula units pf calcium iodide (Cal2) will have what mass?

maw [93]

Answer:

mass CaI2 = 23.424 Kg

Explanation:

From the periodic table we obtain for CaI2:

⇒ molecular mass CaI2: 40.078 + ((2)(126.90)) = 293.878 g/mol

∴ mol CaI2 = (4.80 E25 units )×(mol/6.022 E23 units) = 79.708 mol CaI2

⇒ mass CaI2 = (79.708 mol CaI2)×(293.878 g/mol) = 23424.43 g

⇒ mass CaI2 = 23.424 Kg

7 0

4 years ago

A hamburger containing 335.4 kcal of energy was combusted in a bomb calorimeter with an unknown heat capacity. The temperature o

Zielflug [23.3K]

Answer:

$Cv_{calorimeter}=18.4kcal/K$

Explanation:

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In this case, since the combustion of the hamburger released 335.4 kcal of energy and that energy is received by the calorimeter, we can write:

$Q_{hamburguer}=-Q_{calorimeter}$

And the heat of the calorimeter is written in terms of the temperature change and the calorimeter constant:

$Q_{hamburguer}=-Cv_{calorimeter}\Delta T$

Thus, given the released heat by the hamburger due to its combustion and the temperature change, Cv for the calorimeter turns out:

$Cv_{calorimeter}=\frac{-Q_{hamburguer}}{\Delta T} =\frac{-(-335.4kcal)}{18.2K}\\\\Cv_{calorimeter}=18.4kcal/K$

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4 0

3 years ago

When a 500. gram sample of water at 19.0°C absorbs 8400 Joules of heat, the temperature of the water

Westkost [7]

Answer: 23.0ºC

Explanation:

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7 0

3 years ago

Under identical conditions, separate samples of O2 and an unknown gas were allowed to effuse through identical membranes simulta

Brut [27]

Answer:

The molar mass of unknown gas is 145.82 g/mol.

Explanation:

Volume of oxygen gas effused under time t = 8.24 mL

Effusion rate of oxygen gas = $R=\frac{8.24 mL}{t}$

Molar mass of oxygen gas = 32 g/mol

Volume of unknown gas effused under time t = 3.86 mL

Effusion rate of unknown gas = $R'=\frac{3.86 mL}{t}$

Molar mass of unknown gas = M

Graham's Law states that the rate of effusion or diffusion of gas is inversely proportional to the square root of the molar mass of the gas. The equation given by this law follows the equation:

$\text{Rate of diffusion}\propto \frac{1}{\sqrt{\text{Molar mass of the gas}}}$

$\frac{R}{R'}=\sqrt{\frac{M}{32 g/mol}}$

$\frac{\frac{8.24 mL}{t}}{\frac{3.86 mL}{t}}=\sqrt{\frac{M}{32 g/mol}}$

$M=\frac{32 g/mol\times 8.24 \times 8.24}{3.86\times 3.86}=145.82 g/mol$

4 0

3 years ago

1 mole = _____________________ _________________ particles

Artist 52 [7]

1 mole = 6.02 * 10^23 atoms

This is known as Avogadro's Number. This value is approximate.

5 0

3 years ago

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Which of the following are properties of mechanical waves?​

Which of the following are properties of mechanical waves?