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valentina_108 [34]
3 years ago
11

Someone please help with this thank you!!!

Mathematics
1 answer:
nlexa [21]3 years ago
7 0

Answer:if you add all you get 30 my answer might not be right

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First photo question-The graph below shows three different normal distributions.
zheka24 [161]

Answer:

For the <u>first question</u>:  They must each have a different mean and a different standard deviation.  For the <u>second question</u>:  In an observational study the researchers do not control treatment and in an experiment they do.  For the <u>third question</u>:  The second graph.  For the <u>fourth question</u>:  The second graph.

Step-by-step explanation:

For the <u>first question</u>:  We can see that each bell-shaped curve is centered around a different number.  This tells us that their means are all different.

We can also see that each curve has a different width; this means that the spread of data, measured in part by the standard deviation, is different as well.  This means both the mean and the standard deviation of each distribution is different.

For the <u>second question</u>:  In an observational study, as the name implies, all that is done is observation.  There is no treatment given by the researchers.  In an experiment, however, one group receives treatment and one group does not, so the differences can be measured.

For the <u>third question</u>:  In the first graph, the probabilities add up to 1.2.  This is more than 100%, so this is not a valid distribution.  In the second graph, the probabilities add up to 1.0; this is 100% exactly, so this is a valid distribution.

For the <u>fourth question</u>:  In the first graph, the probabilities only add up to 0.9.  This is not 100%, so this is not a valid distribution.  In the second graph, the probabilities add up to 1.0; this is 100% exactly, so this is a valid distribution.

8 0
4 years ago
Read 2 more answers
Problem: Suppose that on-the-job injuries in textile mill occur at the rate of 0.1 per day. What is the probability that two acc
sertanlavr [38]

Answer: the probability that two accidents will occur during the (five-day) work week is 0.0758

Step-by-step explanation:

Given that;

injuries in textile mill occur at the rate of 0.1 per day; λ = 0.1

probability that two accidents will occur during the (five-day) work week = ?

T= 5

so, the average number of on the job injuries for five days will be;

λT = 0.1 × 5

= 0.5

now if X follows Poisson distribution, hemce

P( X=k ) = [e^-λT (λT)^k] / k!

so the probability that two (2) accidents will occur during the (five-day) work week will be;

P( X=k ) = [e^-0.5 (0.5)²] / 2!

= (0.6065 × 0.25) / 2

= 0.1516/ 2

= 0.0758

the probability that two accidents will occur during the (five-day) work week is 0.0758

3 0
3 years ago
Line AB is parallel to line CD. What is the measure of ∠2?
Helga [31]

Answer:

B

Step-by-step explanation:

its not 90 or above because its acute and its not 10 because that would be almost closed so 80 or B is the only answer

5 0
3 years ago
Can a Lagrange multiplier ever equal zero? If so, in what circumstances?
atroni [7]
No, it can not.
Most times it will just show an error
7 0
3 years ago
One possible major in college is?
FrozenT [24]

Business or doctorate


7 0
4 years ago
Read 2 more answers
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