All categories

2 years ago

A chef has 8 brands of hot sauce. In how many ways can the chef pick 3 to mix into a gumbo?

Mathematics

1 answer:

Tatiana [17]2 years ago

5 0

<h3>Answer: 56</h3>

How to get that answer:

If order mattered, then there would be 8*7*6 = 336 different permutations of sauces. I started with 8 and counted down by 1 until three slots were filled.

That 336 value would be the answer if order mattered; however, it does not matter. For any grouping of three, there are 3*2*1 = 6 ways to order that specific group. This indicates the 336 is too large by a factor of 6.

To fix this, we divide by 6 and we get 336/6 = 56

There are 56 ways to pick the 3 brands from the 8 overall brands to choose from.

You might be interested in

suppose you flip a coin twice. what is the probability that you get tails on the first flip and tail on the second flip?

Nezavi [6.7K]

The possibilities are HH TT HT TH so to get TT you have a 1/4 chance (25%)

4 0

3 years ago

Read 2 more answers

Ricardo S. gave 158 baseball cards to Ayden and 45 cards to Conner. He had 42 cards left. how many baseball cards did Ricardo S.

Inessa05 [86]

Answer:

203 ; 245

Step-by-step explanation:

158 + 45= 203

question 2

203+42= 245

3 0

3 years ago

Read 2 more answers

What is the simplified form of x+8/4-x+5/4

kap26 [50]

Answer:

Step-by-step explanation:

x+ 8/4 -x+ 5/4

= x+2+-x +5/4

Combine Like Terms:

x+2+-x+ 5/4

(x+x)+ ( 2 +5/4)

= 13/4

5 0

3 years ago

Read 2 more answers

you are rolling a 10-sided die with sides numbered 1-10. you keep rolling the die until you roll a prime number and then stop. l

evablogger [386]

The formula for E(x) would be SUM[ X(n)P(n)] from n = 1 to n = infinity until we get the prime number

In the given problem, a 10-sided die with 1-10 numbers is rolled until we get a prime number

Prime numbers between 1-10 = 2,3,5,7 (4 prime numbers)

Non - prime numbers = 1,4,6,8,9,10( 6 non-prime number)

Let X be the number of times the die is rolled

The probability of getting a prime =

$P(Prime) = \frac{4}{10}$

Now, the value of

E(X)=∑x.P(x) [ x-> {1, infinity}]

= P(1)X(1) +P(2)X(2)+P(3)X(3)+P(4)X(4)........+ P(n)X(n)

= 1. $\frac{4}{10}$ + 2. $\frac{6}{10}$ . $\frac{4}{10}$ + 3. $\frac{6}{10}$ . $\frac{6}{10}$ $\frac{4}{10}$ + 4. $\frac{6}{10}$ . $\frac{6}{10}$ . $\frac{6}{10}$ . $\frac{4}{10}$ .......