(A)
P(<em>X</em> < 61.25) = P((<em>X</em> - 55.4)/4.1 < (61.25 - 55.4)/4.1)
… ≈ P(<em>Z</em> ≤ 0.1427)
… ≈ 0.5567
(B)
P(<em>X</em> > 46.5) = P((<em>X</em> - 55.4)/4.1 > (46.5 - 55.4)/4.1)
… ≈ P(<em>Z</em> > -2.1707)
… ≈ 1 - P(<em>Z</em> ≤ -2.1707)
… ≈ 0.9850
((x^2-3x-18)/(x+3))
((x-6)(x+3))/(x+3)
The x+3 on top cancels out the x+3 on the bottom so all you have left is
x-6
Hope I didn't mess up for your sake!
ANSWER
![-\frac{\sqrt[]{3}}{2}](https://tex.z-dn.net/?f=-%5Cfrac%7B%5Csqrt%5B%5D%7B3%7D%7D%7B2%7D)
EXPLANATION
Given
We can find cos 150 by using
recall that
![\begin{gathered} \cos 30=\frac{\sqrt[]{3}}{2} \\ \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20%5Ccos%2030%3D%5Cfrac%7B%5Csqrt%5B%5D%7B3%7D%7D%7B2%7D%20%5C%5C%20%20%5Cend%7Bgathered%7D)
Hence,
![\begin{gathered} \cos 150=-\cos 30 \\ =-\frac{\sqrt[]{3}}{2} \\ \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20%5Ccos%20150%3D-%5Ccos%2030%20%5C%5C%20%3D-%5Cfrac%7B%5Csqrt%5B%5D%7B3%7D%7D%7B2%7D%20%5C%5C%20%20%5Cend%7Bgathered%7D)
Therefore, the value of cos 150 is
Solve for x by simplifying both sides of the equation, than isolating the variable.
x ≤ 8/3 or x ≥ 8
Answer:
width is 33
Step-by-step explanation:
width (b) =?
length(l)=3
perimeter (p)=?
now,
perimeter = 2(l+b)
or,72= 2(3+ b)
or,72/2= 3+b
or,36= 3+b
or,36-3= b
or,33= b
therefore width is 33
