Which is a line of symmetry

Question 6

inna [77]

Answer:

add, subtract, multiply and divide complex numbers much as we would expect. We add and subtract

complex numbers by adding their real and imaginary parts:-

(a + bi)+(c + di)=(a + c)+(b + d)i,

(a + bi) − (c + di)=(a − c)+(b − d)i.

We can multiply complex numbers by expanding the brackets in the usual fashion and using i

2 = −1,

(a + bi) (c + di) = ac + bci + adi + bdi2 = (ac − bd)+(ad + bc)i,

and to divide complex numbers we note firstly that (c + di) (c − di) = c2 + d2 is real. So

a + bi

c + di = a + bi

c + di ×

c − di

c − di =

µac + bd

c2 + d2

¶

+

µbc − ad

c2 + d2

¶

i.

The number c−di which we just used, as relating to c+di, has a spec

7 0

1 year ago

I just need to know the horizontal part I can do the other. Please ASAP

11Alexandr11 [23.1K]

Answer:

Enjoy and it would be good if you gave more points

Step-by-step explanation:

6 0

2 years ago

Help. How do u convert units within a measurement system

Triss [41]

Step 1. Identify the unit you have
Step 2. Identify the unit you want to covert to
Step 3. Count the number of units between them

(If you are going from a larger unit to a smaller unit, you multiply by 10 successively.)

4 0

2 years ago

. Lightning Strikes It has been said that the probability of being struck by lightning is about 1 in 750,000, but under what cir

mrs_skeptik [129]

Complete Question

The complete question is shown on the first uploaded image

Answer:

a

$P(U |D ) = 0.198$

b

$P(O\ n \ B) = 0.188$

c

$P(O | B) = 0.498$

Step-by-step explanation:

The total number of deaths is mathematically represented as

$T = 16 + 23 + \cdots + 16$

$T =623$

The total number of deaths in 1996 - 2000 is mathematically represented as

$T_a = 16 + 23+ \cdots + 30$

$T_a = 235$

The total number of deaths in 2001 - 2005 is mathematically represented as

$T_b = 17 + 16 + \cdots + 23$

$T_b = 206$

The total number of deaths in 2006 - 2010 is mathematically represented as

$T_c = 15 + 17 + \cdots + 16$

$T_d = 182$

Generally the the probability that it would occur under the tree given that the death was after 2000 is mathematically represented as

$P(U |D ) = \frac{P(A \ n\ U )}{P(A)}$

Here $P(A \ n\ U )$ represents the probability that it was after 2000 and it was under the tree and this is mathematically represented as

$P(A \ n\ U ) = \frac{Z}{ T}$

Here Z is the total number of death under the tree after 2000 and it is mathematically represented as

$Z = 35 + 42$

=> $Z = 77$

=> $P(A \ n\ U ) = \frac{77}{ 623}$

=>

Also

$P(A)$ is the probability of the death occurring after 2000 and this is mathematically represented as

$P(A) = \frac{T_b + T_c}{ T}$

=> $P(A) = \frac{ 206+ 182}{623}$

=>

So

$P(U |D ) = \frac{\frac{77}{ 623} }{ \frac{ 206+ 182}{623}}$

=> $P(U |D ) = 0.198$

Generally the probability that the death was from camping or being outside and was before 2001 is mathematically represented as

$P(O | B) = \frac{T_z}{ T}$

Here $T_z$ is the total number of death outside / camping before 2001 and the value is 117

So

$P(O \ n \ B) = \frac{117}{623}$

=> $P(O\ n \ B) = 0.188$

Generally the probability that the death was from camping or being outside given that it was before 2001 is mathematically represented as

$P(O | B) = \frac{ P( O \ n \ B)}{ P(B)}$

Here $P(B)$ is the probability that it was before 2001 , this is mathematically represented as

$P(B ) = \frac{T_a}{T}$

=> $P(B ) = \frac{235}{623}$

So

$P(O | B) = \frac{ \frac{117}{623}}{ \frac{235}{623}}$

=> $P(O | B) = 0.498$

5 0

2 years ago

List this from least to greatest: .5, 3/16, .75, 5.48

pashok25 [27]

List this from least to greatest:.5, 3/16, .75, 5.48

3/16 = 0.1875

so from least to greatest

3/16, .5, .75, 5.48

5 0

2 years ago