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2 years ago

HELPPPPPPPP Write the standard form of an equation

Mathematics

1 answer:

vovangra [49]2 years ago

4 0

Answer:

See the Answer Below:) I am certain this is the answer

Step-by-step explanation:

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$4000 for 2years at 5% compounded quarterley

NeTakaya

$\bf \qquad \textit{Compound Interest Earned Amount}
\\\\
A=P\left(1+\frac{r}{n}\right)^{nt}
\qquad 
\begin{cases}
A=\textit{accumulated amount}\\
P=\textit{original amount deposited}\to &\$4000\\
r=rate\to 5\%\to \frac{5}{100}\to &0.05\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{quarterly, meaning 4 times}
\end{array}\to &4\\

t=years\to &2
\end{cases}$

5 0

2 years ago

The number of milligrams of a certain medicine a veterinarian gives to a dog varies directly with the weight of the dog. If the

sineoko [7]

W/6=d

Because 30 is 6 times 5

4 0

3 years ago

What is the solution to the system of equations 2x-y=7 and y=2x+3

Yuri [45]

Make y the subject in both equations

$2x-y=7$

$-y=-2x+7$

$y=2x-7$

For the second equation

$y=2x+3$

The two equations are parallel because they have the same gradient or slope but different y intercepts.

This type of equations have no solution because they will never intersect.

$NO SOLUTION$

The correct answer is C

6 0

2 years ago

What is 10 + 10 + 10 + 10 + 10

lidiya [134]

Answer:

50 easy

Step-by-step explanation:

8 0

2 years ago

Read 2 more answers

Find the value of x and the length of both chords if BW=2x+10, WD=4, CW=7x+5, and WE=2.

daser333 [38]

Answer:

The value of x is 5

The lengths of the chords are 24 units and 42 units

Step-by-step explanation:

In a circle if two chords intersected at a point inside it there are four segments created, two in each cord, the products of the lengths of the line segments on each chord are equal

∵ BD and CE are two chords in a circle intersected at W

∴ The two segments of chord BD are BW and WD

∴ The two segments of chord CE are CW and WE

- By using the rule above

∴ BW × WD = CW × WE

∵ BW = 2x + 10 and WD = 4

∵ CW = 7x + 5 and WE = 2

- Substitute them in the rule above

∴ (2x + 10) × 4 = (7x + 5) × 2

∴ 4(2x) + 4(10) = 2(7x) + 2(5)

∴ 8x + 40 = 14x + 10

- Subtract 14x from both sides

∴ - 6x + 40 = 10

- Subtract 40 from both sides

∴ - 6x = - 30

- Divide both sides by - 6

∴ x = 5

∵ Chord BD = 2x + 10 + 4

∴ Chord BD = 2x + 14

- Substitute the value of x to find its length

∴ Chord BD = 2(5) + 14 = 10 + 14

∴ Chord BD = 24 units

∵ Chord CE = 7x + 5 + 2

∴ Chord CE = 7x + 7

- Substitute the value of x to find its length

∴ Chord CE = 7(5) + 7 = 35 + 7

∴ Chord CE = 42 units

5 0

2 years ago