A1 = 4
a2 = 5a1 = 5 x 4 = 20
a3 = 5a2 = 5 x 20 = 100
a4 = 5a3 = 5 x 100 = 500
a5 = 5a4 = 5 x 500 = 2,500
Tn = ar^(n-1); where a = 4, r = 5
Tn = 4(5)^(n-1) = 4/5 (5)^n
Explicit formular is Tn = 4/5 (5)^n
Recursive formular is
Answer:
A. 12+2p
G. p+p+12
Step-by-step explanation:
The Eagles basketball team scored 12 more than 2 times as many points in the last game of the season than in the first game
Number of points scored in the last game of the season = 2p + 12
A. 12+2p
Equivalent
B. 2+p+12
= P + 14
Not equivalent
C. 2+12p
Not equivalent
D. p(2+12)
= 2p + 12p
Not equivalent
E. p+2+12
= P + 14
Not equivalent
F. 12p+2p
Not equivalent
G. p+p+12
= 2p + 12
Equivalent
The smallest positive integer that the intermediate value theorem guarantees a zero exists between 0 and a is 3.
What is the intermediate value theorem?
Intermediate value theorem is theorem about all possible y-value in between two known y-value.
x-intercepts
-x^2 + x + 2 = 0
x^2 - x - 2 = 0
(x + 1)(x - 2) = 0
x = -1, x = 2
y intercepts
f(0) = -x^2 + x + 2
f(0) = -0^2 + 0 + 2
f(0) = 2
(Graph attached)
From the graph we know the smallest positive integer value that the intermediate value theorem guarantees a zero exists between 0 and a is 3
For proof, the zero exists when x = 2 and f(3) = -4 < 0 and f(0) = 2 > 0.
<em>Your question is not complete, but most probably your full questions was</em>
<em>Given the polynomial f(x)=− x 2 +x+2 , what is the smallest positive integer a such that the Intermediate Value Theorem guarantees a zero exists between 0 and a ?</em>
Thus, the smallest positive integer that the intermediate value theorem guarantees a zero exists between 0 and a is 3.
Learn more about intermediate value theorem here:
brainly.com/question/28048895
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Answer:
Step-by-step explanation:
f'(x)=-2x+7
f(x) is decreasing if '(x)<0
so -2x+7<0
or 7<2x
or 2x>7
or x>7/2
including end points f(x) is decreasing in [3/2,∞)
Answer:
Step-by-step explanation:
(-1,5)....x1 = -1 and y1 = 5
(-5,-5)..x2 = -5 and y2 = -5
slope = (y2 - y1) / (x2 - x1)
slope = (-5 - 5) / (-5 - (-1) = -10 / (-5 + 1) = -10/-4 = 5/2 <===