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gavmur [86]
2 years ago
7

Both the National Fire Academy and Iowa formulas calculate the flow requirement for structures that are __________ percent invol

ved in flame.
Chemistry
1 answer:
emmainna [20.7K]2 years ago
7 0

Answer:

100

Explanation:

You might be interested in
Which nuclei are most useful for organic structure determination using nmr spectroscopy? (select all that apply.)?
Mumz [18]
Hydrogen-1, Carbon-13, Nitrogen-15, Fluorine-19, and Phosphorus-31 are the most useful. Out of these, Hydrogen-1 and Carbon-13 in NMR are the most useful nuclei because the these atoms are the most commonly present in organic molecules.
5 0
3 years ago
How many 250 mg tablets of metronidazole are needed to make 150 mL of suspension containing
Neko [114]

Answer:

How many 250 mg tablets of metronidazole are needed to make 150 mL of suspension containing

100 mg/mL?

a. 25

b. 30

c.50

d. 60

Explanation:

<em>if </em><em> </em><em>mali </em><em>po </em><em>I'm</em><em> </em><em>so </em><em>sorry</em>

7 0
3 years ago
How many molecules are in 42.3g sample of water
Helga [31]

Answer:

The number of molecules is 1.4140*10^24 molecules

Explanation:

To know the number of molecules, we need to determine how many moles of water we have, water has molar mass of 18.015g/mol

This means that one mole of water molecules has a mass of 18.015g.

42.3g * 1 mole H2O/18.015g

= 2.3480 moles H2O

We are using avogadros number to find the number of molecules of water

2.3480 H2O * 6.022*10^ 23moles/ 1mole of H2O

That's 2.3480 multiplied by 6.022*10^23 divided by 1 mole of H2O

Number of molecules = 1.4140 *10^24 molecules

5 0
3 years ago
What is the molality of sodium chloride in solution that is 13.0% by mass sodium chloride and that has a density of 1.10 g/ml?
8090 [49]
Answer is: molality od sodium chloride is 2,55 mol/kg.
V(solution) = 100 ml.
m(solution) = d(solution) · V(solution).
m(solution) = 1,10 g/ml · 100 ml.
m(solution) = 110 g.
ω(NaCl) = 13,0% = 0,13.
m(NaCl) = ω(NaCl) · m(solution).
m(NaCl) = 0,13 · 110 g.
m(NaCl) = 14,3 g.
n(NaCl) = m(NaCl) ÷ M(NaCl).
n(NaCl) = 14,3 g ÷ 58,5 g/mol.
n(NaCl) = 0,244 mol.
m(H₂O) = 110 g - 14,3 g.
m(H₂O) = 95,7 g = 0,0957 kg.
b(NaCl) = n(NaCl) ÷ m(H₂O).
b(NaCl) = 0,244 mol ÷ 0,0957 kg.
b(NaCl) = 2,55 mol/kg.
3 0
3 years ago
Give the number of covalent bonds that a carbon atom can form.
polet [3.4K]

Answer:

four covalent bonds

Explanation:

A carbon atom would form 4 covalent bonds.

For a covalent bond to be formed, an atom would share its valence electrons with another. In this process, each atom would require unpaired electrons for this bond to be formed. The number of available unpaired electrons would represent the number of electrons needed to complete the outer energy level of the atom.

In a carbon atom, we have no lone pair of electrons and 4 unpaired electrons. When these 4 electrons are shared with those of other atoms, they produce a complete octet which perfectly mimics the noble gases.

3 0
3 years ago
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