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gavmur [86]
2 years ago
7

Both the National Fire Academy and Iowa formulas calculate the flow requirement for structures that are __________ percent invol

ved in flame.
Chemistry
1 answer:
emmainna [20.7K]2 years ago
7 0

Answer:

100

Explanation:

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The density of silver is 10.49 g/mL. If a sample of pure silver has a volume of 12.993 mL, what is the mass of the silver?
r-ruslan [8.4K]

Answer:

see the pic for more detail

4 0
2 years ago
What is the density of CO2 at a pressure of 0.0079 atm and 227 K? (These are the approximate atmospheric in Mars)
Strike441 [17]

Answer:

The density is 0.0187 g/L

Explanation:

First thing to do here is to calculate the Volume of 1 mole of CO2 using the ideal gas equation

Mathematically;

PV = nRT

thus V = nRT/P

what we have are;

n = 1 mole

R is the molar has constant = 0.082 L•atm•mol^-1•K^-1

P is the pressure = 0.0079 atm

T is temperature = 227 K

Substituting these values, we have;

V = nRT/P = (1 * 0.082 * 227)/0.0079

V = 2,356.20 dm^3

This means according to the parameters given in the question, the volume of 1 mole of carbon iv oxide is 2,356.20 dm^3

But this is not what we want to calculate

What we want to calculate is the density

Mathematically, we can calculate the density using the formula below;

density = molar mass/molar volume

Kindly recall that the molar mass of carbon iv oxide is 44 g/mol

Thus the density = 44/2356.20 = 0.018674136321195 which is approximately 0.0187 g/L

6 0
3 years ago
The diagram below shows the different phase transitions that occur in matter.
Nimfa-mama [501]

The arrow that represents the transition in which dew is formed would be arrow 4.

<h3>How is dew formed?</h3>

Dew is formed by condensation. Condensation, in itself, involves a transition from a gas phase to a liquid phase.

From the diagram, the arrow that represents a transition from gas to liquid is arrow 4.

Thus, the arrow that represents the transition that leads to the formation of dew would be arrow 4.

More on dew formation can be found here: brainly.com/question/23169635

#SPJ1

3 0
1 year ago
Read 2 more answers
Please help with #2 and #3
Vaselesa [24]

Answer:

2. V_2=17L

3. V=82.9L

Explanation:

Hello there!

2. In this case, we can evidence the problem by which volume and temperature are involved, so the Charles' law is applied to:

\frac{V_2}{T_2}=\frac{V_1}{T_1}

Thus, considering the temperatures in kelvins and solving for the final volume, V2, we obtain:

V_2=\frac{V_1T_2}{T_1}

Therefore, we plug in the given data to obtain:

V_2=\frac{18.2L(22+273)K}{(45+273)K} \\\\V_2=17L

3. In this case, it is possible to realize that the 3.7 moles of neon gas are at 273 K and 1 atm according to the STP conditions; in such a way, considering the ideal gas law (PV=nRT), we can solve for the volume as shown below:

V=\frac{nRT}{P}

Therefore, we plug in the data to obtain:

V=\frac{3.7mol*0.08206\frac{atm*L}{mol*K}*273.15K}{1atm}\\\\V=82.9L

Best regards!

6 0
3 years ago
If the actual yield of sodium chloride from the reaction of
lions [1.4K]

If the actual yield of sodium chloride from the reaction of 8.3 g of sodium and 4.5 g of chlorine is 6.4 g, what is the percent yield?

 

Answer : 2Na(s) + Cl2(g) → 2NaCl(s)

Explanation: Friend me!!!

7 0
2 years ago
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