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liubo4ka [24]
2 years ago
13

Is sugar a compound or a mixture?

Chemistry
2 answers:
pogonyaev2 years ago
5 0

Compound, since it is not mixed with anything.

i just took tests on chemicals and elements, and i remember this.

puteri [66]2 years ago
3 0

Answer:

compound

Explanation:

You might be interested in
If the complete conversion of 1.383g of XI2 results in the formation of 0.564g of XCl2,what is the atomic mass of the element X
Marina CMI [18]

Answer:

So X has an atomic mass of 55.05 u, and is probably Mn

Explanation:

<u>Step1: </u>Balance the equation

XI2 +Cl2 →  XCl2 + I2

<u>Step2:</u> find the molar mass of the compounds

<em><u>Compounds : </u></em>

X  ⇒ Molar mass = M

XI2 ⇒ Molar mass = M + 2*126.9 u

XCl2 ⇒Molar mass = M + 2*35.45u

⇒For 1 mole XI2 we have 1 mole Cl2 reacting , as well as 1 mole XCl2 and 1 mole I2 produced.

<u>Step 3:</u> Calculating the atomic mass

(1.383g * XI2) / (M + 2*126.90 u)  = (0.564g * XCl2) / ( M + 2 * 35.45u)

1.383 (M + 2 *35.45 u )= 0.564 (M  + 2*126.90)

1.383M + 98.0547 = 0.564 M + 143.1432

1.383 M - 0.564 M =143.1432 - 98.0547

0.819 M = 45.0885

M = 55.05 u

So X has an atomic mass of 55.05 u ⇒ if we look at the periodic table we can find that the closest element is Manganese (Mn)

MnI2 + Cl2 → MnCl2 + I2

5 0
3 years ago
С14H30= 3C2H4 + ? <br><br>Please help I'm really bad with science lol​
harkovskaia [24]

Answer:

me too? HAHAHHAHAHAHAHAHAHAHAHHA

6 0
3 years ago
In an experiment magnesium ribbon was heated in air. The product was found to be heavier than the original ribbon. Potassium man
KatRina [158]

Burning a magnesium ribbon in the air is an addition reaction while heating potassium manganate 7 is a decomposition reaction.

<h3>Addition and decomposition reactions</h3>

Magnesium burns in air to produce magnesium oxide as follows:

2Mg + O_2 --- > 2MgO

Potassium manganate 7 burns to produce multiple products as follows:

2 KMnO_4 --- > K_2MnO_4 + MnO_2(s) + O_2

Thus, the MgO will be heavier than Mg. On the other hand, MnO_2 will be less heavy than KMnO_4.

More on reactions can be found here: brainly.com/question/17434463

#SPJ1

7 0
2 years ago
True or false:The nucleus is the largest part of the atom and takes up most space
alexira [117]
It has the most mass. but the electron cloud takes up the most space.
5 0
3 years ago
I need help with 1,2,3, and 4
Schach [20]

Answer:

  • Problem 1: 1.85atm
  • Problem 2: 110mL
  • Problem 3: 290 mL
  • Problem 4: 1.14 atm

Explanation:

Problem 1

<u>1. Data</u>

<u />

a) P₁ = 3.25atm

b) V₁ = 755mL

c) P₂ = ?

d) V₂ = 1325 mL

r) T = 65ºC

<u>2. Formula</u>

Since the temeperature is constant you can use Boyle's law for idial gases:

          PV=constant\\\\P_1V_1=P_2V_2

<u>3. Solution</u>

Solve, substitute and compute:

         P_1V_1=P_2V_2\\\\P_2=P_1V_1/V_2

        P_2=3.25atm\times755mL/1325mL=1.85atm

Problem 2

<u>1. Data</u>

<u />

a) V₁ = 125 mL

b) P₁ = 548mmHg

c) P₁ = 625mmHg

d) V₂ = ?

<u>2. Formula</u>

You assume that the temperature does not change, and then can use Boyl'es law again.

          P_1V_1=P_2V_2

<u>3. Solution</u>

This time, solve for V₂:

           P_1V_1=P_2V_2\\\\V_2=P_1V_1/P_2

Substitute and compute:

        V_2=548mmHg\times 125mL/625mmHg=109.6mL

You must round to 3 significant figures:

        V_2=110mL

Problem 3

<u>1. Data</u>

<u />

a) V₁ = 285mL

b) T₁ = 25ºC

c) V₂ = ?

d) T₂ = 35ºC

<u>2. Formula</u>

At constant pressure, Charle's law states that volume and temperature are inversely related:

         V/T=constant\\\\\\\dfrac{V_1}{T_1}=\dfrac{V_2}{T_2}

The temperatures must be in absolute scale.

<u />

<u>3. Solution</u>

a) Convert the temperatures to kelvins:

  • T₁ = 25 + 273.15K = 298.15K

  • T₂ = 35 + 273.15K = 308.15K

b) Substitute in the formula, solve for V₂, and compute:

        \dfrac{V_1}{T_1`}=\dfrac{V_2}{T_2}\\\\\\\\\dfrac{285mL}{298.15K}=\dfrac{V_2}{308.15K}\\\\\\V_2=308.15K\times285mL/298.15K=294.6ml

You must round to two significant figures: 290 ml

Problem 4

<u>1. Data</u>

<u />

a) P = 865mmHg

b) Convert to atm

<u>2. Formula</u>

You must use a conversion factor.

  • 1 atm = 760 mmHg

Divide both sides by 760 mmHg

       \dfrac{1atm}{760mmHg}=\dfrac{760mmHg}{760mmHg}\\\\\\1=\dfrac{1atm}{760mmHg}

<u />

<u>3. Solution</u>

Multiply 865 mmHg by the conversion factor:

    865mmHg\times \dfrac{1atm}{760mmHg}=1.14atm\leftarrow answer

3 0
3 years ago
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