Answer:
So X has an atomic mass of 55.05 u, and is probably Mn
Explanation:
<u>Step1: </u>Balance the equation
XI2 +Cl2 → XCl2 + I2
<u>Step2:</u> find the molar mass of the compounds
<em><u>Compounds : </u></em>
X ⇒ Molar mass = M
XI2 ⇒ Molar mass = M + 2*126.9 u
XCl2 ⇒Molar mass = M + 2*35.45u
⇒For 1 mole XI2 we have 1 mole Cl2 reacting , as well as 1 mole XCl2 and 1 mole I2 produced.
<u>Step 3:</u> Calculating the atomic mass
(1.383g * XI2) / (M + 2*126.90 u) = (0.564g * XCl2) / ( M + 2 * 35.45u)
1.383 (M + 2 *35.45 u )= 0.564 (M + 2*126.90)
1.383M + 98.0547 = 0.564 M + 143.1432
1.383 M - 0.564 M =143.1432 - 98.0547
0.819 M = 45.0885
M = 55.05 u
So X has an atomic mass of 55.05 u ⇒ if we look at the periodic table we can find that the closest element is Manganese (Mn)
MnI2 + Cl2 → MnCl2 + I2
Answer:
me too? HAHAHHAHAHAHAHAHAHAHAHHA
Burning a magnesium ribbon in the air is an addition reaction while heating potassium manganate 7 is a decomposition reaction.
<h3>Addition and decomposition reactions</h3>
Magnesium burns in air to produce magnesium oxide as follows:

Potassium manganate 7 burns to produce multiple products as follows:

Thus, the MgO will be heavier than Mg. On the other hand,
will be less heavy than
.
More on reactions can be found here: brainly.com/question/17434463
#SPJ1
It has the most mass. but the electron cloud takes up the most space.
Answer:
Explanation:
Problem 1
<u>1. Data</u>
<u />
a) P₁ = 3.25atm
b) V₁ = 755mL
c) P₂ = ?
d) V₂ = 1325 mL
r) T = 65ºC
<u>2. Formula</u>
Since the temeperature is constant you can use Boyle's law for idial gases:

<u>3. Solution</u>
Solve, substitute and compute:


Problem 2
<u>1. Data</u>
<u />
a) V₁ = 125 mL
b) P₁ = 548mmHg
c) P₁ = 625mmHg
d) V₂ = ?
<u>2. Formula</u>
You assume that the temperature does not change, and then can use Boyl'es law again.

<u>3. Solution</u>
This time, solve for V₂:

Substitute and compute:

You must round to 3 significant figures:

Problem 3
<u>1. Data</u>
<u />
a) V₁ = 285mL
b) T₁ = 25ºC
c) V₂ = ?
d) T₂ = 35ºC
<u>2. Formula</u>
At constant pressure, Charle's law states that volume and temperature are inversely related:

The temperatures must be in absolute scale.
<u />
<u>3. Solution</u>
a) Convert the temperatures to kelvins:
- T₁ = 25 + 273.15K = 298.15K
- T₂ = 35 + 273.15K = 308.15K
b) Substitute in the formula, solve for V₂, and compute:

You must round to two significant figures: 290 ml
Problem 4
<u>1. Data</u>
<u />
a) P = 865mmHg
b) Convert to atm
<u>2. Formula</u>
You must use a conversion factor.
Divide both sides by 760 mmHg

<u />
<u>3. Solution</u>
Multiply 865 mmHg by the conversion factor:
