C6H12O6 -------> 6 C + 6 H20
moles C6H12O6 = ( 1745 g ) / ( 180 g/mol ) = 96.94 mol C6H12O6
mol C produced = ( 96.94 mol C6H12O6 reacted ) ( 6 mol C made / mol C6H12O6 reacted )
mol C produced = 58.17 moles C produced <-----------------------
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Answer:
pH = 7.45
Explanation:
This is a buffer solution and we can solve it by using the Henderson-Hasselbalch equation:
pH = pKa + log ((A⁻)/(HA))
Here we will first have to calculate the A⁻ formed in the 1. 0 L solution which is formed by the reaction of HClO with the strong base NaOH and add it to the original mol of NaClO
mol NaClO = mole NaCLO originally present in the 1L of M solution + 0.030 mol produced in the reaction of HCLO with NaOH
0.350 mol + .030 mol = 0.380 mol
New concentrations :
HClO = 0. 350 mol-0.030 mol = 0.320 M (have to sustract the 0.030 mol reacted with NaOH)
NaClO = 0.380 mol/ 1 L = 0.380 M
Now we have all the values required and we can plug them into the equation
pH = -log (2.9 x 10^-8) + log (0.380/.320) = 7.45
Matter and energy, and both these things are made up of atoms
It releases all types of pollution into the air, as well as potentially endangering birds and other wildlife that live near that forest.
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D is the correct answer for your question. Maybe I am not sure.