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3 years ago

Propane has a long standing reputation for being a ______burning fuel

1 answer:

4 0

I'm pretty sure its flammable hydrocarbon for the blank spot cause that's what i learned but i'm not sure. Just trying to help, IMAO!

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How many neutrons are present in 1 atom of chlorine?

pav-90 [236]

The answer is A.18 let me know if you want an explanation

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3 years ago

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Which does your digestive system use to break down food molecules? Bases or Acids

Harman [31]

Answer:

acid

Explanation:

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3 years ago

Why are models used for understanding cells

liraira [26]

Because when you use a model you can see the cells and understand where they are located and how they work. Also a model helps you visual because you can't see cells so a model helps.

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3 years ago

You are burning wood to heat water for your industrial process. What is the mass of wood required to raise the temperature of 10

natta225 [31]

Answer:

18,8kg of wood

Explanation:

The energy you need to to raise the temperature of 1000 kg of water from 25.0 to 100.0 °C is:

q = C×m×ΔT

Where: q is heat, C is specific heat of water (4,184J/g°C), m is mass in grams (1000x10³g), and ΔT is 100,0°C - 25,0°C = 75,0°C

Replacing:

q = 4,184J/g°C×1000x10³g×75,0°C

q = 3,14x10⁸ J of heat are required

Now, if the heating value of dry wood is 16,72 MJ/kg = 16,72x10⁶ J/kg, mass of wood required is:

3,14x10⁸J × (1kg / 16,72x10⁶ J) = 18,8 kg of wood are required

I hope it helps!

5 0

3 years ago

A glass laboratory flask is filled with gas at 24 ∘C and 0.95 atm pressure, sealed, and then heated to 104 ∘C. What is the press

Elan Coil [88]

The pressure inside the flask on heating it is given as 1.21 atm.

Explanation:

As per Guy Lussac's law, the pressure of any concealed volume of gas particles will be directly proportional to the temperature of the container of the gas particles.

So P ∝ T

To convert celsius to kelvin, add 273.15 to the temperature value in celsius

Since, here the initial temperature of the flask is given as 24°C, so in kelvin it will be 297.15 K. Similarly, the final temperature is said to be 104°C which will be equal to 377.15 K. Then the final pressure will be increased as there is increase in temperature. So, the final pressure inside the flask can be obtained as

$\frac{P_{1} }{T_{1} } = \frac{P_{2} }{T_{2} }$

$P_{2} = \frac{P_{1} }{T_{1} } \times T_{2} =\frac{0.95}{297.15} \times 377.15 =1.21\ atm$

So, the pressure inside the flask on heating it is given as 1.21 atm.

3 0

4 years ago