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otez555 [7]
3 years ago
7

The reaction of hydrogen and iodine to produce hydrogen iodide has a Kc of 54.3 at 703 K. Given the initial concentrations of H2

and I2 are 0.453 M, what will the concentration of HI be at equilibrium
Chemistry
1 answer:
pentagon [3]3 years ago
3 0

Answer:

[HI] = 0.7126 M

Explanation:

Step 1: Data given

Kc = 54.3

Temperature = 703 K

Initial concentration of H2 and I2 = 0.453 M

Step 2: the balanced equation

H2 + I2 ⇆ 2HI

Step 3: The initial concentration

[H2] = 0.453 M

[I2] = 0.453 M

[HI] = 0 M

Step 4: The concentration at equilibrium

[H2] = 0.453 - X

[I2] = 0.453 - X

[HI] = 2X

Step 5: Calculate Kc

Kc = [Hi]² / [H2][I2]

54.3 = 4x² / (0.453 - X(0.453-X)

X = 0.3563

[H2] = 0.453 - 0.3563 = 0.0967 M

[I2] = 0.453 - 0.3563 = 0.0967 M

[HI] = 2X = 2*0.3563 = 0.7126 M

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Answer:

The amount of solute added.

Explanation:

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Monatomic ions: Ca^{2+, O^{2-, and Fe^{3+

<h3>Monoatomic vs Polyatomic Ions</h3>

In chemistry, monoatomic ions are ions that consist of only a single type of atom. They are usually positive or negatively charged and are otherwise known as simple ions. Examples include  Ca^{2+, O^{2-, and Fe^{3+

Polyatomic ions, on the other hand, are ions that consist of more than one atom, unlike monoatomic ions. The two or more atoms are covalently bonded and the entire structure behaves like a single chemical entity in reactions. Polyatomic ions are otherwise known as molecular ions.

Examples of polyatomic ions are  CH_3COO^-, NO_3^-, NH^+, CN^-, Li^+, and OH^-

Thus, from the diagram:

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6 0
10 months ago
You react 2.33 g of iron (III) chloride with 50.0 mL of 0.500 M solution of sodium phosphate to
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Answer:

2.33g of iron (iii) chloride

50.0 mL of 5.00 M of sodium phosphate

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x = 0.0025 × 3 = 0.075 mol NaCl

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2 years ago
Gold is formed in pure state in nature but not iron,why?​
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Explanation:

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Explanation:

Given data:

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Number of grams = ?

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