Question

A 150 g egg is dropped from 3.0 meters. The egg is moving at 4.4 m/s right before it hits the ground. The egg comes to a stop in 0.072 seconds.
What is the magnitude of force that the ground exerted on the egg?

0.66 N
9.2 N
13 N
180 N

Answer 1

Answer:

  (b)  9.2 N

Step-by-step explanation:

The acceleration is the change in velocity divided by the change in time:

  a = (-4.4 m/s)/(0.072 s) = -61 1/9 m/s²

The force is given by ...

  F = ma = (0.150 kg)(-61 1/9 m/s²) = -9 1/6 N ≈ -9.2 N

The ground exerts a force of about 9.2 N upward on the egg.