Answer:
a) weight of the car = 2816,1 lbs
b) 2773 lbs
Step-by-step explanation:
The equilibrium force is 490 lbs. That force keep the car at rest, then
∑ Fy = 0 and ∑Fx = 0
Forces acting on the car:
The external force 490 lbs
weight of the car uknown
Normal force
sin∠10° = 0,174
cos∠10° = 0.985
∑Fx = 0 mg*sin10°- 490 = 0 ∑Fy = 0 mg*cos10° - N = 0
mg*0,174= 490
mg = 490 / 0,174
mg = 2816,1 lbs
weight of the car = 2816,1 lbs
The Normal force
mg*cos10° - N = 0 2816,1 * 0,985 = N
N = 2773 lbs
Then equal force in magnitude and in opposite direction will car exets on the driveway
That’s what i got
step by step explanation
Surface area o fthe ball = 4 * 3.14 * radius^2
if diameter = 1.680 then radius = 1/2 * 1.680 = 0.84
so surface area = 4 * 3.14 * 0.84^2 = 8.862
414 divided by 2= 207
divided by 2 because two times the number
207 hamburgers sold
36÷6 is 6 to show your work for it maybe draw it out and better show the equation like when you solve a bigger problem.
