Answer:
The probability that a corn crop has either an ear worm infestation, a corn borer infestation
P(EUB) = 0.27
Step-by-step explanation:
<u>Explanation</u>:-
<u>Addition theorem on probability</u>:-
If S is a sample space, and E , F are any events in S then
P(EUF) = P(E) +P(F) -P(E n F)
Let 'E' be the event that a corn crop has an infestation of ear worms
let 'B' be the event that a corn crop has an infestation of corn bores
P(EUB) = P(E) +P(B) -P(E n B)
given P(E) = 0.24 and P(B) = 0.16 and P(E n B) =0.13
P(EUB) = P(E) +P(B) -P(E n B)
P(EUB) = 0.24 + 0.16 - 0.13
= 0.27
The probability that a corn crop has either an ear worm infestation, a corn borer infestation
P(EUB)=0.27
Answer:
a) Statement is true
b) Statement incorrect. Company goal is to attend customer at 190 second at the most. So test should be one tail test (right)
c) We have to reject H₀, and differences between sample mean and the hypothesized population mean should not be attributed only to sampling error
Step-by-step explanation:
a) as the significance level is = 0,02 that means α = 0,02 (the chance of error type I ) and the β (chance of type error II is
1 - 0.02 = 0,98
b) The company establishe in 190 seconds time for customer at its ticket counter (if this time is smaller is excellent ) company is concerned about bigger time because that could be an issue for customers. Therefore the test should be a one test-tail to the right
c) test statistic
Hypothesis test should be:
null hypothesis H₀ = 190
alternative hypothesis H₀ > 190
t(s) = ( μ - μ₀ ) / s/√n ⇒ t(s) = ( 202 - 190 )/(28/√100 )
t(s) = 12*10/28
t(s) = 4.286
That value is far away of any of the values found for 99 degree of fredom and between α ( 0,025 and 0,01 ). We have to reject H₀, and differences between sample mean and the hypothesized population mean should not be attributed only to sampling error
If we look table t-student we will find that for 99 degree of freedom and α = 0.02.
Type I error says that we suppose that the null hypothesis exists rejected when in reality the null hypothesis was actually true.
Type II error says that we suppose that the null hypothesis exists taken when in fact the null hypothesis stood actually false.
<h3>
What is
Type I error and Type II error?</h3>
In statistics, a Type I error exists as a false positive conclusion, while a Type II error exists as a false negative conclusion.
Making a statistical conclusion still applies uncertainties, so the risks of creating these errors exist unavoidable in hypothesis testing.
The probability of creating a Type I error exists at the significance level, or alpha (α), while the probability of making a Type II error exists at beta (β). These risks can be minimized through careful planning in your analysis design.
Examples of Type I and Type II error
- Type I error (false positive): the testing effect says you have coronavirus, but you actually don’t.
- Type II error (false negative): the test outcome says you don’t have coronavirus, but you actually do.
To learn more about Type I and Type II error refer to:
brainly.com/question/17111420
#SPJ4
Answer:
Step-by-step explanation:
A 45 degree angle in a right triangle produces 2 equal sides. In this case z and the perpendicular line are equal. So that's were we'll start. Then you move on to the 60 degree angle to get x and y.
Finding z
z^2 + z^2 = (24√2) Combine the left
2z^2 = 24^2 * 2 Divide both sides by 2
2z^2/2 = 24^2/2
z^2 = 24^2 Take the square root of both sides
√z^2 = √24^2
z = 24
Finding x and y
The perpendicular = 24. Because it is a 60 degree angle that's given, we can do this without a calculator.
Tan 60 = opposite over adjacent
sqrt(3) = Perpendicular / z Multiply both sides by z
z*sqrt(3) = perpendicular
The above calculation tells us the perpendicular is 24
z*sqrt(3) = 24 Divide by sqrt 3
z = 24/√3
z = 24/1.73
z = 8√3
Finding x
Use Pythagoras to determine x
Perpendicular^2 + (8√3)^2 = x^2
24^2 + 8^2*3 = x^2
576 + 192 = x^2
768 = x^2
√x^2 = √768
x = 27.71
Find the perimeter of the yard ( the distance around the yard).
A rectangle has two sides of each dimension.
The perimeter is 20 + 20 + 45 + 45 = 130 feet.
Now multiply the total feet by the cost per foot:
130 feet x 25 per foot = $3,250 total.
