Answer: sometimes, there are a lot of rectangles that are composite shapes so that could work. also, most composite shapes have two dimensions.
Step-by-step explanation:
Answer:
Step-by-step explanation:
=> 20 + 12k - 7k - 8
=> 20 - 8 + 12k - 7k
=> 12 + 5k
=> 12 + 5k
<u>Hence correct answer is 12</u><u> </u><u>+</u><u> </u><u>5</u><u>k</u><u>.</u>
Answer:
The probability that the total weight of the passengers exceeds 4222 pounds is 0.0018
Step-by-step explanation:
The Central limit Theorem stays that for a large value of n (21 should be enough), the average distribution X has distribution approximately normal with mean equal to 182 and standard deviation equal to 30/√21 = 6.5465. Lets call W the standarization of X. W has distribution approximately N(0,1) and it is given by the formula

In order for the total weight to exceed 4222 pounds, the average distribution should exceed 4222/21 = 201.0476.
The cummulative distribution function of W will be denoted by
. The values of
can be found in the attached file.

Therefore, the probability that the total weight of the passengers exceeds 4222 pounds is 0.0018.
Answer:
x=6
Step-by-step explanation:
Simplify
-2/x+4=4/x+3
4=6/x+3
6/x=1
x=6
Answer:
(x+5), (y-3) -----> reflect over line x = 3
Step-by-step explanation: