Answer:
0.07973 moles of O2 gas were produced
2.66 atm
Explanation:
Using the ideal gas equation
PV =nRT
P =pressure = 2.9 atm
V= volume = 720 mL = 720mL/1000= 0.72 L
n = number of moles = ?
R = the gas constant = 0.0821 atm L/(mol K)
T = temperature in Kelvin = 319 K
make n subject of the formula
n =PV/RT
n = 2.9 atm x 0.72 L / 0.0821 atm L/(mol K) x 319K = 0.07973 moles of O2 gas were produced
Pnew = atm?
P = nRT/V
= 0.07973 x 0.0821 atm L/(mol K) x 293K/0.72 L = 2.66 atm
Answer:
The external pressure is p = -21.9 psf or p = -8.85 psf
Explanation:
Given :
Velocity of wind, v = 120 mi / hr
(wind direction factor)
= topographical factor (for flat terrain)
= velocity pressure at height h
But for height h = 30 ft, = 0.98 (from table)
= 36.16
Now, , so (from table)
where, p = external pressure
G = 0.85 = gust factor (for typical rigid building)
(internal pressure co efficient)
Therefore putting the values,
p = -21.9 psf or p = -8.85 psf