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Dmitriy789 [7]
3 years ago
5

In a CNC machining operation, the has to be moved from point (5, 4) to point(7, 2)along a circular path with center at (7,2). Be

fore starting operation, the tool is at (5, 4).The correct G and M code for this motion is
Engineering
1 answer:
notka56 [123]3 years ago
6 0

Answer: hello your question is incomplete below is the complete question

answer:

N010 GO2 X7.0 Y2.0 15.0 J2.0  ( option 1 )

Explanation:

Given that the NC machining has to be moved from point ( 5,4 ) to point ( 7,2 ) along a circular path

GO2 = circular interpolation in a clockwise path

G91 = incremental dimension

<em>hence the correct option is </em>:

N010 GO2 X7.0 Y2.0 15.0 J2.0  

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If datums are used as suggested below (A datum on shaft, B datum on face below the head, C datum on the hex flat) and order of p
allsm [11]

Answer:

a. Use datum on shaft

b. Use datum on hex flat

c. Use datum on face below the head

d. Use datum on shaft

When these datum are used, they will prevent translation and rotation along axis which they act.

6 0
4 years ago
State the two Carnot corollaries (principles)
Salsk061 [2.6K]

Answer  and Explanation:

The two principles or corollaries of Carnot Theorem are listed below:

1). The efficiencies of all the reversible heat engines between any two thermal reservoirs working between the same temperatures will be equal to each other.

2). For every Carnot engine working between any two thermal reservoirs will have the same efficiency independent of the operating conditions and the nature of working substance. It only depends on the temperature of the thermal energy reservoirs.

8 0
4 years ago
4.In a hydroelectric power plant, 100 m3/s of water flows from an elevation of 120 m to a turbine, where electric power is gener
Dmitrij [34]

Answer:

The rate of irreversible loss will be "55.22 MW".

Explanation:

The given values are:

Elevation,

h = 120 m

Flow of water,

Q = 100 m³/s

Efficiency,

= 80%

i.e,

= 0.8

Efficiency turbine,

= 50 MW

Now,

Without any loss,

The power generated by turbine will be:

⇒ P=\delta gQh

On substituting the values, we get

⇒     =1000\times 9.8\times 100\times 120

⇒     =117.72 \ MW

Power generated in actual will be:

= \frac{50}{0.8}

= 62.5 \ MW

Hence,

Throughout the piping system,

The rate of irreversible loss is:

= Power \ generated \ by \ turbine-Power \ generated  \ in \ actual

= 117.72-62.5

= 55.22 \ MW

4 0
3 years ago
Please help me with this question​
kap26 [50]

Answer:

The current through each lamp is 0.273 Amperes

Power dissipated in each lamp is 0.082W

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Battery v = 1.5 V

Each lamp has resistance, r = 1.1 Ohms

The 5 lamps in series will therefore have total resistance, R = 5 * 1.1 = 5.5 Ohms

The current through each lamp, I = v/R = 1.5 / 5.5 = 0.273 Amperes

Power dissipated in each lamp = I² * r = 0.273² * 1.1 = 0.082W

3 0
3 years ago
Why do side airbags say inflated for several seconds
Pavlova-9 [17]

Answer:

When the airbag is activated, the chemicals produce heated nitrogen gas, which inflates the nylon bag....

hope my answer help u!!!!

7 0
4 years ago
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