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marissa [1.9K]
4 years ago
5

A current powered by a battery is called what?

Engineering
1 answer:
Ann [662]4 years ago
7 0
Your answer is electromotive force
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iogann1982 [59]
It’s engineering gnzvxhfhbkchufkh
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3 years ago
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A scale model is 4th the size of the pump. Determine the power ratio of the pump and its scale model if the ratio of the heads i
vredina [299]

Given:

size of scale model = 4(size of pump)

power ratio of pump and scale model = 5:1

Solution:

Let the diameter of scale model and pump be d_{s} and d_{p} respectively

and head be  H_{s} and  H_{p} respectively

Now, power, P is given as a function of head(H) and dischagre(Q)

P = \rho gQH                  (1)

From eqn (1):

P \propto QH

and

QH \propto \sqrt{H}D^{2}

So,

P \propto H^{\frac{3}{2}} D^{2}

Therefore,

\frac{P_{s}}{P_{p}} = \frac{D_{s}^{2} H_{s}^{\frac{3}{2}}}{D_{p}^{2} H_{p}^{\frac{3}{2}}}

\frac{P_{s}}{P_{p}} = \frac{D_{s}^{2} H_{s}^{\frac{3}{2}}}{D_{p}^{2} H_{p}^{\frac{3}{2}}}

\frac{P_{s}}{P_{p}} = \frac{1^{2}\times 5^{\frac{3}{2}}}{4^{2}\times 1^{\frac{3}{2}}}

\frac{P_{s}}{P_{p}} = \frac{5\sqrt{5}}{16}

{P_{s}}:{P_{p}} = {5\sqrt{5}}:{16}

8 0
3 years ago
What is the magnitude of the maximum stress that exist at the tip of an internal crack having a radius of curvature of 1.9 x 10-
Hitman42 [59]

Answer:

2800 [MPa]

Explanation:

In fracture mechanics, whenever a crack has the shape of a hole, and the stress is perpendicular to the orientation of such, we can use a simple formula to calculate the maximum stress at the crack tip

\sigma_{m} = 2 \sigma_{p} (\frac{l_{c}}{r_{c}})^{0.5}

Where \sigma_{m} is the magnitude of he maximum stress at the tip of the crack, \sigma_{p} is the magnitude of the tensile stress, l_{c} is 1/2 the length of the internal crack, and r_{c} is the radius of curvature of the crack.

We have:

r_{c}=1.9*10^{-4} [mm]

l_{c}=3.8*10^{-2} [mm]

\sigma_{c}=140 [MPa]

We replace:

\sigma_{m} = 2*(140 [MPa])*(\frac{\frac{3.8*10^{-2} [mm]}{2}}{1.9*10^{-4} [mm]})^{0.5}

We get:

\sigma_{m} = 2*(140 [MPa])*(\frac{\frac{3.8*10^{-2} [mm]}{2}}{1.9*10^{-4} [mm]})^{0.5}=2800 [MPa]

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3 years ago
Could a volcanic eruption suddenly bury a city and its inhabitants? (Plz explain to me)
andrezito [222]
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Exercise 5.46 computes the standard deviation of numbers. This exercise uses a different but equivalent formula to compute the s
ruslelena [56]

Answer:

// This program is written in Java Programming Language

// Comments are used for explanatory purpose

// Program starts here

import java.util.Scanner;

public class STDeviation {

// Declare and Initialise size of Numbers to be 10

int Numsize = 10;

public static void main(String args [] ) {

Scanner scnr = new Scanner(System.in);

// Declare digits as double

double[] digits = new double[Numsize];

System.out.print("Enter " + Numsize + " digits: ");

// Input digits using iteration

for (int i = 0; i < digits.length; i++)

{

digits[i] = scnr.nextDouble();

}

// Calculate and Print Mean/Average

System.out.print("Average: " + mean(digits)+'\n');

// Calculate and Print Standard Deviation

System.out.println("Standard Deviation: " + deviation(digits));

}

// Standard Deviation Module

public static double deviation(double[] x) {

double mean = mean(x);

// Declare and Initialise deviation to 0

double deviation = 0;

// Calculate deviation

for (int i = 0; i < x.length; i++) {

deviation += Math.pow(x[i] - mean, 2);

}

// Calculate length

int len = x.length - 1;

return Math.sqrt(deviation / len);

}

// Mean Module

public static double mean(double[] x) {

// Declare and Initialise total to 0

double total = 0;

// Calculate total

for (int i = 0; i < x.length; i++) {

total += x[i];

}

// Calculate length

int len = x.length;

// Mean = total/length

return total / len;

}

}

4 0
3 years ago
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