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Jet001 [13]
3 years ago
7

What is quality? Does it have any meaning in the superheated vapor region?​

Physics
1 answer:
beks73 [17]3 years ago
6 0

Answer:

Fraction of vapor in liquid-vapor region is called quality. since in superheated zone all the liquid has been vaporised hence it doesn't have any meaning in superheated region.

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Erwin Schrödinger developed the quantum model of the atom. What scientific knowledge was necessary for Schrödinger’s work?
Stella [2.4K]

Answer:

Erwin Schrödinger developed the quantum model of the atom. What scientific knowledge was necessary for Schrödinger's work? The discovery of the electron.

Explanation:

7 0
2 years ago
A cylindrical capacitor has an inner conductor of radius 1.5 mm andan outer conductor of radius 3.4 mm.The two conductors are se
kenny6666 [7]

Answer:

Part(a): The capacitance per unit length of the capacitor is \bf{1.56 \times 10^{-10}}~F~m^{-1}.

Part(b): The charge in the inner shell is + 1.6 \times 10^{-10}~C and the charge of the outer shell is - 1.6 \times 10^{-10}~C.

Explanation:

Part(a):

The capacitance (C) per unit length of a cylindrical capacitor is given by

C = \dfrac{2 \pi \epsilon_{0}}{log(b/a)}

where '\epsilon_{0}' is the permittivity of free space, 'b' is the radius of the outer shell and 'a' is the radius of the inner shell.

Given, b = 3.4~mm = 0.0034~m and a = 1.5~mm = 0.0015~m. We know, \epsilon_{0} = 8.854 \times 10^{-12}~F~m^{-1}. Substituting the values in the above equation,

C = \dfrac{2 \pi \times 8.85 \times 10^{-12}~F~m^{-1}}{log(0.0034/0.0015)} = 1.56 \times 10^{-10}~F~m^{-1}

Part(b):

As the voltage on the inner conductor is higher than that of the outer conductor, positive charge resides on the inner shell and negative charge resides on the outer shell.

The charge 'Q' of a capacitor of length 'L' having capacitance 'C' and potential difference 'V' is given by

Q = C~V~L

Given, V = 350~mV = 350 \times 10^{-3}~V and L = 3.0~m. Substituting these values in the above expression

Q = 1.56 \times 10^{-10}~F~m^{-1} \times 350 \times 10^{-3}~V \times 3~m = 1.6 \times 10^{-10}~C

The charge in the inner shell is + 1.6 \times 10^{-10}~C and the charge of the outer shell is - 1.6 \times 10^{-10}~C.

7 0
4 years ago
A ball is dropped from the top of a cliff. By the time it reaches the ground, all of its gravitational potential energy has been
Katena32 [7]

Answer:

20 m

Explanation:

Initial potential energy = final kinetic energy

mgh = 1/2 mv²

gh = 1/2 v²

h = v² / (2g)

Given v = 20 m/s and g = 10 m/s²:

h = (20 m/s)² / (2 × 10 m/s²)

h = 20 m

4 0
3 years ago
a) A 32-pound weight stretches a spring 2 feet. Determine the amplitude and period of motion if the weight is released 1 foot ab
Shtirlitz [24]

Answer:

Explanation:

Value of spring constant K = weight / extension

=\frac{32\times32}{2}

=512 ft s⁻²

Frequency of oscillation of spring mass system

= \sqrt{\frac{k}{m} }

Putting the values we get

frequency

=[tex]\sqrt{\frac{512}{32} }[/tex]

= 4  .

Time period = 1 / frequency = .25 s

No of vibrations in 4π second

= \frac{4\pi }{.25}

= 50 approx

When the weight is released 1 foot above equilibrium

PE stored = 1/2 K x² = .5 x 512 x 1 = 256 J

KE = 1/2 mv² = .5 x 32 x 4 = 64 J

Total energy =  320 J

Let x be the amplitude upto which spring stretches due to this energy

1/2 k x² = 320 ,

1/2 x 512  x² = 320

x = 1.12 ft approx

6 0
4 years ago
Apply Newton's first law to music playing on the radio.
AnnyKZ [126]

Answer: Find the answer in the explanation

Explanation:

The music playing on the radio will be heard through the sound waves coming from the radio.

The travelling wave will obey Newton's first law of motion which state that:

An object or particle will remain at rest or continue its linear motion in a straight line except an external force is applied.

The external force through wind could affect the travelling of the sound waves. Since the wave is longitudinal wave. That is, it needs a medium (air) for its propagation.

7 0
4 years ago
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