Answer:
The electric potential at the surface of a charged conductor<u> is always such that the potential is zero at all points inside the conductor.</u>
Explanation:
Each point on the surface of a balanced charged conductor has the same electrical potential.
The surface on any charged conductor in electrostatic equilibrium is an equipotential surface. Since the electric field is equal to zero inside the conductor, the electric potential at any point inside and on the surface is equivalent to its value.
Answer:
a. The moment of the 4 N force is 16 N·m clockwise
b. The moment of the 6 N force is 12 N·m anticlockwise
Explanation:
In the figure, we have;
The distance from the point 'O', to the 6 N force = 2 m
The position of the 6 N force relative to the point 'O' = To the left of 'O'
The distance from the point 'O', to the 4 N force = 4 m
The position of the 4 N force relative to the point 'O' = To the right of 'O'
a. The moment of a force about a point, M = The force, F × The perpendicular distance of the force from the point
a. The moment of the 4 N force = 4 N × 4 m = 16 N·m clockwise
b. The moment of the 6 N force = 6 N × 2 m = 12 N·m anticlockwise.
Answer:
14cm
Explanation:
Mass per gram of the piece of wire;
2g of the wire is found in 1m
Since
100cm = 1m;
So;
100cm of the wire contains 2g of the wire
To provide 0.28g
Since;
2g of wire is made up of 100cm
0.28g of wire will be contained in 
= 14cm
14cm of the wire will contain 0.28g
Answer:
0.1371 * 10 ^ -27 kg
Explanation:
From the question number of hydrogen nuclei used to form 3 Helium nuclei = 12 ( 4 * 3 )
mass of the 12 hydrogen nuclei = 12 *( 1.6726 *10^-27) = 20.0712 * 10 ^-27
mass of single helium = 6.6447 * 10 ^-27 kg
therefore the mass of the 3 helium = 3 *( 6.6447 *10 ^-27) = 19.9341 * 10 ^-27 kg
The mass difference between the hydrogen and the helium used
= (20.0712 * 10^ -27) - (19.9341 * 10 ^-27) = 0.1371 * 10 ^ -27 kg
therefore 0.1371 * 10^-27 kg is converted into energy to create the three helium nuclei
Answer:
the answer from my side is both vertical and horizontal
