Answer:
v=2.88 m/s
Explanation:
Given that
R= 0.85 m
The minimum speed of the bucket to prevent the water from falling out given as
Where
R=Radius of the circular arc
g=Acceleration due to gravity
We are taking g= 9.81 m/s²
Now by putting the values
v=2.88 m/s
Therefore the speed of the bucket should be 2.88 m/s.
Answer:
F = 10 [N]
Explanation:
To solve this problem we must use Newton's second law, which tells us that the sum of forces on a body is equal to the product of mass by acceleration.
∑F = m*a
where:
F = forces [N]
m = mass = 0.05 [kg]
a = acceleration = 200 [m/s²]
![F =m*a\\F = 0.05*200\\F = 10 [N]](https://tex.z-dn.net/?f=F%20%3Dm%2Aa%5C%5CF%20%3D%200.05%2A200%5C%5CF%20%3D%2010%20%5BN%5D)
earths precession so its B
The crowbar is placed under a small edge under the top of the box. The crowbar will send the box lid flying from the opposite direction that the crowbar is placed. Please give Brainlest if you understand.
<span>conservation of momentum
mass(ball) × speed(ball) = mass(cannon) × speed(cannon)
(8.3 kg) × (187.9 m/s) = (949.3 kg) × v
1.64 m/s = v
</span>
