A ball is dropped from the top of a cliff. By the time it reaches the ground, all of its gravitational potential energy has been
1 answer:
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Answer:
Explanation:
The magnitude of the acceleration in the x direction is always zero: TRUE.
At the apex, in the y direction the velocity is zero and the accelration is positive. TRUE.
At the apex, in the x direction, the velocity is zero and the acceleration is zero. FALSE. The accelration is zero, but the velocity is the same it had when it was shot.
The magnitude of the velocity in the y direction is always constant. FALSE, it's subject to gravity and it's velocity varies as
At the apex, in the Y direction, the velocity is negative and the acceleration is zero. FALSE. Velocity is zero, Acceleration is , towards the negative y axis
Answer:
v = 2.82 m/s
Explanation:
For this exercise we can use the conservation of energy relations.
We place our reference system at the point where block 1 of m₁ = 4 kg
starting point. With the spring compressed
Em₀ = K_e + U₂ = ½ k x² + m₂ g y₂
final point. When block 1 has descended y = - 0.400 m
Em_f = K₂ + U₂ + U₁ = ½ m₂ v² + m₂ g y₂ + m₁ g y
as there is no friction, the energy is conserved
Em₀ = Em_f
½ k x² + m₂ g y₂ = ½ m₂ v² + m₂ g y₂ + m₁ g y
½ k x² - m₁ g y = ½ m₂ v²
v² =
let's calculate
v² =
v² = 2.7 + 5.23
v = √7.927
v = 2,815 m / s
using of significant figures
v = 2.82 m/s
Answer:
The atomic number increases by 1.
Explanation:
The beta minus decay is a process in which a neutron decays into a proton, emitting an electron and an anti-neutrino:
If this process occurs inside an unstable nucleus, we notice that:
- a neutron is converted into a proton, therefore
- the number of neutrons decreases by 1 and the number of protons increases by 1
Keep in mind that the atomic number of a nucleus corresponds to the number of protons it contains: therefore, since this number increases by 1, then the atomic number increases by 1.