Answer:
<em>The magnitude of the force is 10 N</em>
Explanation:
<u>Coulomb's Law</u>
The electrostatic force between two charged objects is directly proportional to the product of their charges and inversely proportional to the square of the distance between the two objects.
Written as a formula:
Where:
q1, q2 = the objects' charge
d= The distance between the objects
We have two identical charges of q1=q2=1 c separated by d=30000 m, thus the magnitude of the force is:
F = 10 N
The magnitude of the force is 10 N
Hello
1) The work W is calculated as the product between the force F applied to the cart and the distance d covered by the cart:
2) The force is the product of the mass m of the cart and its acceleration a:
If we use this into the formula of the work, we get
3) The cart is moving by accelerated motion. For this kind of motion, we have the following relationship:
where
and
are the final and the initial velocity of the cart.
Re-arranging we have
4) Therefore, we can subsitute
into the original formula of the work, and we get
Answer:
1.36m/s
Explanation:
We are given that
Mass of one acrobat,
Mass of another acrobat,
We have to find their velocity immediately after they grab onto each other.
The collision between two acrobat is inelastic
According to law of conservation of momentum
Substitute the values
Answer:
The speed of the vehicles immediately after the collision is 5.84 m/s.
Explanation:
The speed of the vehicles after the collision can be found by conservation of linear momentum:
Where:
m₁: is the mass of the car = 0.5 ton = 500 kg
m₂: is the mass of the lorry = 9.5 ton = 9500 kg
: is the initial speed of the car = 40 km/h = 11.11 m/s
: is the initial speed of the lorry = 20 km/h = 5.56 m/s
: is the final speed of the car =?
: is the final speed of the lorry =?
Since the two vehicles become tightly locked together after the collision = :
Therefore, the speed of the vehicles immediately after the collision is 5.84 m/s.
I hope it helps you!
Answer:
This result is a very good approximation, because R>>d
Explanation:
The capacitance for two parallel flat plates, with surface S, space between them d, is:
This calculation is based on the fact that the electric field is constant between the plates. This only happens if the area of the plates is much larger than the distance between them: S>>d, i.e. R>>d. If we assume these factors, the result has a very good approximation.