How do you solve m=10x-x for x

Mathematics

1 answer:

cricket20 [7]3 years ago

3 0

<span>m=10x-x for x
first subtract x from 10x

m=9x
divide both sides by 9

m/9=x

x=m/9</span>

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Plz help me!!!

disa [49]

~kites have adjacent sides equal~

x = 3x-12

move 3x to the other side as a negative number

-2x = -12

divide both sides by -2

-12 divided by -2 is 6

so, x is equal to 6

but, we aren't done yet because the questions asks for the value of angle b

substitute the value we found into the equation for angle b

3(6)-12

36-12

24

so, angle b has a value of 24 degrees

7 0

2 years ago

Will mark Brainliest if someone can help me!!!!! (Idk if Prinicipal is right 2-5)

Talja [164]

$\bf ~~~~~~ \textit{Compound Interest Earned Amount} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill &\$1500\\ r=rate\to r\%\to \frac{r}{100}\dotfill &0.04\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{annually, thus once} \end{array}\dotfill &1\\ t=years\dotfill &1,2,3,4,5 \end{cases}$

$\bf A=1500\left(1+\frac{0.04}{1}\right)^{1\cdot 1}\implies A=1500(1.04)^1\implies A\approx 1560\\\\\\A=1500\left(1+\frac{0.04}{1}\right)^{1\cdot 2}\implies A=1500(1.04)^2\implies A\approx 1622.4\\\\\\A=1500\left(1+\frac{0.04}{1}\right)^{1\cdot 3}\implies A=1500(1.04)^3\implies A\approx 1687.3\\\\\\A=1500\left(1+\frac{0.04}{1}\right)^{1\cdot 4}\implies A=1500(1.04)^4\implies A\approx 1754.79\\\\\\A=1500\left(1+\frac{0.04}{1}\right)^{1\cdot 5}\implies A=1500(1.04)^5\implies A\approx 1824.98$