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Verdich [7]
3 years ago
13

Work is a transfer of (1 point) energy. force. mass. motion.

Physics
2 answers:
olya-2409 [2.1K]3 years ago
8 0

Answer: Work is a transfer of energy.

Explanation:

Energy is the ability to do work. The energy can be transferred to do work.

Work is done whenever the energy is transferred from one form to another.

To do work, the force is applied through distance.

The force is applied to an object to bring in motion.

Therefore, work is a transfer of energy.

jok3333 [9.3K]3 years ago
6 0
Energy is the ability to do work.

So work can not be done without the transfer of energy from one body to another.

Work is the transfer of energy.
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Air at 27oC and 1 atm flows over a flat plate 40 cm in length and 1 cm in width at a speed of 2 m/s. The plate is heated over it
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Answer:

Heat transferred = 22.9 watt

Explanation:

Given that:

T_1 = 27°C = (273 + 27) K = 300 K

T_2= 600°C = (600 +273) K = 873 K

speed v = 2 m/s

length x = 40 cm = 0.4 cm

width = 1 cm = 0.001 m

The heat transferred from the plate can be calculate by using the formula:

Heat transferred = h×A ×ΔT

From the tables of properties of air, the following values where obtained.

k = 0.02476 \ W/m.k  \\ \\  \rho = 1.225 \ kg/m^3 \\ \\ \mu = 18.6 \times 10^{-6} \ Pa.s \\ \\ c_p = 1.005 \ kJ/kg

To start with the reynolds number; the formula for calculating the reynolds number can be expressed as:

reynolds number = \dfrac{\rho \times v \times x }{\mu}

reynolds number = \dfrac{1.225 \times 2 \times 0.4}{18.6 \times 10^{-6}}

reynolds number = \dfrac{0.98}{18.6 \times 10^{-6}}

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Prandtl number = \dfrac{c_p \mu}{k}

Prandtl number = \dfrac{1.005 \times 18.6 \times 10^{-6} \times 10^3}{0.02476}

Prandtl number = \dfrac{0.018693}{0.02476}

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The nusselt number for this turbulent flow over the flat plate  can be computed as follows:

Nusselt no = \dfrac{hx}{k} = 0.0296 (Re) ^{0.8} \times (Pr)^{1/3}

\dfrac{h \times 0.4}{0.02476} = 0.0296 (52688.11204) ^{0.8} \times (0.754968)^{1/3}

\dfrac{h \times 0.4}{0.02476} =161.4252008}

h  =\dfrac{161.4252008 \times 0.02476}{ 0.4}

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Recall that:

The heat transferred from the plate can be calculate by using the formula:

Heat transferred = h×A ×ΔT

Heat transferred = h\times A \times (T_2-T_1)

Heat transferred = 9.992 × (0.4 × 0.01) ×(873-300)

Heat transferred = 22.9 watt

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