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irakobra [83]
2 years ago
14

What is the correct answer?

Mathematics
1 answer:
Svetlanka [38]2 years ago
4 0

Answer:

Terms must have the same variable (letter) and the same exponent (little number)

(7x² +3y+ 5) +(9x²+11y- 2)

Opening bracket

7x²+3y+5+9x²+11y-2

keeping like terms together

7x²+9x²+3y+11y+5-2

Since terms having same variable and exponent can be subtracted, added,divided and multiplied

So

Solving like terms we get

<u>16x²+14y+3</u> which is a correct answer.

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Step-by-step explanation:

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What is the range of the function f(x) = 3x2 + 6x – 8?
timama [110]

Answer:

Range is {y | y ≥ –11}


Step-by-step explanation:

This is quadratic equation.

<em>A quadratic equation's range can be found if we find the vertex.</em>

For quadratic equations that have a positive number in front of  x^{2} , it is upward opening and thus <u>all the numbers greater than or equal to the minimum value of vertex is the range.</u>


The formula for vertex of a parabola is:

Vertex =  (-\frac{b}{2a}, f(-\frac{b}{2a})

Where,

  • a is the coefficient of x^{2}
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From our equation given, a=3  and  b=6

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y coordinate of the vertex IS THE MINIMUM VALUE that we want. We get this by plugging in the x value [ x=-1 ] into the equation. So we have:

3(-1)^{2}+6(-1)-8\\=-11


Hence, the range would be all numbers greater than or equal to -11  

Third answer choice is the right one.


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