All categories

3 years ago

Pls help do tmr, I'll give brainliest!!

Mathematics

2 answers:

Maslowich3 years ago

5 0

Less than. Reasoning: 75x2=150. So the reverse is 150/2. So to find the other, divide 100 by 2. 100/2=50. 50<75

Ann [662]3 years ago

4 0

Answer:

Answer Below

Step-by-step explanation:

75 is 50% of 150. In that case, w is 50% of 100. 50% of 100 is 50, so w=50. This means that w is less than 75.

You might be interested in

Which table shows a function that is decreasing over the interval (−2, 0)?

zhenek [66]

Answer : Image 3

Which table shows a function that is decreasing over the interval (−2, 0)?

We look at the interval -2 to 0 on x

In option 1 table , f(x) is 0 then -5 and then becomes 0

It means -2 to -1 , f(x) decreases but from -1 to 0 y values increases

In option 2 table , f(x) is increasing from -15 to -5

In option 3 table, f(x) values goes on decreasing over the interval -2 to 0

So , option 3 table shows a function that is decreasing over the interval (−2, 0)

8 0

3 years ago

Read 2 more answers

Please help!! 15 Points!!!!

Ray Of Light [21]

Answer:

I think it is ether A are B

3 0

3 years ago

Read 2 more answers

Below?

labwork [276]

Answer:

-2x-8=10, x=-9

Step-by-step explanation:

After all transactions as wee see nothing's changed but we add '-' to all. And we get -2x-8=10 and -2x=18; x=18/-2=-9

3 0

3 years ago

Please answer those three question

EleoNora [17]

1- Three and one-hundred thousandths. Tenths
2- Five and two hundred and sixty seven thousandths. Hundredths.

5 0

3 years ago

The school that Scott goes to is selling tickets to a fall musical. On the first day of ticket sales the school sold 12 adult ti

harina [27]

Answer:

The price of one adult ticket = $13

The price of one student ticket = $4

Step-by-step explanation:

Let the price of 1 adult ticket = x

Let the price of 1 student ticket = y

On the first day of ticket sales the school sold 12 adult tickets and 10 student tickets for a total of $196.

12 × x + 10 × y = $196

12x + 10y = 196....... Equation 1

The school took in $59 on the second day by selling 3 adult tickets and 5 student tickets

3 × x + 5 × y = $59

3x + 5y = 59.......... Equation 2

Using Elimination method

We eliminate y, by Multiplying equation 1 by 5 and Equation 2 by 10

12x + 10y = 196....... Equation 1 × 5

3x + 5y = 59.......... Equation 2 × 10

60x + 50y = 980....... Equation 3

30x + 50y = 590......... Equation 4

Subtract Equation 4 from Equation 3

30x = 390

x = 390/30

x = $13

Therefore, the price of one adult ticket = $13

Remember: x = $13

3x + 5y = 59.......... Equation 2

Substitute

3(13) + 5y = 59

39 + 5y = 59

5y = 59 - 39

5y = 20

y = 20/5

y = $4

Therefore, the price of one student ticket = $4

8 0

3 years ago