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3 years ago

What do you already know about gases?

Chemistry

1 answer:

viktelen [127]3 years ago

4 0

Answer:

gasese molecules are always in free state

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Which statement about silver (Ag) metal is least reliable?

brilliants [131]

The answer to the question is the first opti.on.A

8 0

3 years ago

Read 2 more answers

Strontium oxide + ? =<br>stronium chloride

White raven [17]

Answer:

strontium oxide + hydrochloric acid (HCL) = strontium chloride

8 0

3 years ago

g The first step in the process is to calibrate the grating, so we know the grating spacing (the distance between the openings i

Trava [24]

Answer:

The grating spacing is $d = 1055nm$

Explanation:

From the question we are told that

The wavelength is $\lambda = 590 nm = 590 *10^{-9}m$

The angle is $\theta = 34^0$

The order of the spectrum is $n = 1$

Generally in grating grating the condition for maxima to occur is

$d sin \theta = n \lambda$

where d is the grating spacing

making d the subject of the formula

$d = \frac{\lambda }{sin \theta }$

Substituting values

$d = \frac{590 * 10^{-9}}{sin (34)}$

$d = 1055nm$

8 0

3 years ago

Consider the calculation of the pressure in kilopascals exerted by 1.25 g of nitrogen gas in a flask of volume 250 mL (0.250 dm3

Harrizon [31]

The amount of the nitrogen gas, N₂ molecules present is 2.68×10²² molecules

<h3>Avogadro's hypothesis </h3>

1 mole of N₂ = 6.02×10²³ molecules

<h3>How to determine the mole of N₂</h3>

We'll begin by calculating the number of mole of N₂. This can be obtained as follow:

Mass of N₂ = 1.25 g
Molar mass of N₂ = 28.02 g/mol
Mole of N₂ =?

Mole = mass / molar mass

Mole of N₂ = 1.25 / 28.02

Mole of N₂ = 0.0446 mole

<h3>How to determine the molecules of N₂ present</h3>

From Avogadro's hypothesis,

1 mole of N₂ = 6.02×10²³ molecules

Therefore,

0.0446 mole N₂ = 0.0446 × 6.02×10²³

0.0446 mole N₂ = 2.68×10²² molecules

Thus, the molecules of N₂ present is 2.68×10²² molecules

Learn more about Avogadro's number:

brainly.com/question/26141731

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6 0

2 years ago

PLEASE HELP! WILL GIVE BRAINLIEST:

Ad libitum [116K]

2.45 °C

From the Ideal gas law (Combined gas law)

PV/T = P'V'/T' .....eq 1

Where:

P - initial pressure

V - initial volume

T - initial temperature

P' - final pressure

V' - final volume

T' - final temperature.

To proceed we have to make T the subject from eq.1

Which is, T = P'V'T/PV.......eq.2

We have been provided with;

Standard temperature and pressure (STP)

P = 760 mm Hg (SP - Standard Pressure)

T = 273.15 K (ST - Standard Temperature)

V = 62.65 L

P' = 612.0 mm Hg

V' = 78.31 L

T' = ? (what we require)

Therefore, we substitute the values into eq.2

T' =

T' = 275.60 K

T = (275.60 - 273.15) ......To °C

T = 2.45 °C

>>>>> Answer

Have a nice studies.

5 0

2 years ago