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Romashka [77]
3 years ago
13

What is the percent composition of Br in CuBr3?

Chemistry
1 answer:
tekilochka [14]3 years ago
6 0

Answer:

about 79% (79.04369332 to be exact)

Explanation:

Percent composition=(Molar mass of element x amount of it)/Molar mass of compound x 100

Br= 3 x 79.9/303.25 x100=79.04369332

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Please help! If a forensic chemist discovers evidence through examination which would prove a person guilty of a crime, why then
Bogdan [553]

Explanation: You cannot be convicted of a crime without evidence. You cannot be convicted of a state crime. You cannot be convicted of a federal crime. If there is no evidence against you, under the law, it simply is not possible for the prosecutor's office to obtain a conviction at trial. So, when you do have evidence it is really impossible to not get convicted unless the judge truly believes your side of the story and declares you not guilty.

I hope this helped :) If not i'm sorry!

7 0
3 years ago
Using VSEPR theory which of the following would be the correct shape for nitrogen trifluoride?
RUDIKE [14]

Answer:

trigonal pyramidal

Explanation:

In NF3, the nitrogen atom is sp3 hybridized. Now we must remember that according to the VSEPR theory, the number of electron pairs in the valence shell of the central atom in a molecule determines its shape.

Here, the nitrogen atom is the central atom and its outermost shell is surrounded by four electron pairs - one lone pair and three bond pairs. This means that it has a tetrahedral electron pair geometry.

However, due to the lone pair, the three fluorine atoms are arranged in a  trigonal pyramidal geometry. Hence the correct shape of the molecule is trigonal pyramidal.

6 0
3 years ago
What is the empirical formula for a substance that is composed of 40.66% carbon, 8.53% Hydrogen,23.72% Nitrogen, and 27.09% Oxyg
prohojiy [21]

Answer:

THE EMPIRICAL FORMULA OF THE SUBSTANCE IS C2H5NO

Explanation:

The steps involved in calculating the empirical formula of this substance in shown in the table below:

Element                            Carbon           Hydrogen          Nitrogen         Oxygen

1. % Composition              40.66              8.53                 23.72                27.09

2. Mole ratio =

%mass/ atomic mass       40.66/12         8.53/1          23.72/14            27.09/16

                                       =  3.3883            8.53              1,6943             1.6931

3. Divide by smallest

value (0.6931)          3.3883/1.6931    8.53/1.6931    1.6943/1.6931   1.6931/1.6931

                               =      2.001                  5.038           1.0007                      1

4. Whole number ratio        2                       5                   1                               1

The empirical formula = C2H5NO

7 0
3 years ago
PLEASE PLEASE PLEASE HELP ME CHEM! DUE IN 10 MINS!! 20 POINTS (SPAM COMMENTS WILL BE BLOCKED) GIVING OUT BRAINLIEST
geniusboy [140]

Answer:

Natrium oxide

4 Na atoms

2 O atoms

Fluoride

6 F atoms

Lithium sulfate

8 Li atoms

16 SO atoms

Calcium

2 Ca atoms

Aluminum hydroxide

2 Al atoms

3 OH atoms

Manganese sulfate

2 Mn atoms

12 SO atoms

Cuprum chloride

1 Cu atom

2 CI atoms

8 0
3 years ago
A reaction in the laboratory yields 5.98 g KAI(SO2)2, How many moles of potassium aluminum
Ivahew [28]

Answer:

0.0308 mol

Explanation:

In order to convert from grams of any given substance to moles, we need to use its molar mass:

  • Molar mass of KAI(SO₂)₂ = MM of K + MM of Al + (MM of S + 2*MM of O)*2
  • Molar mass of KAI(SO₂)₂ = 194 g/mol

Now we <u>calculate the number of moles of KAI(SO₂)₂ contained in 5.98 g</u>:

  • 5.98 g ÷ 194 g/mol = 0.0308 mol
6 0
3 years ago
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