Explanation:
It is known that for high concentration of
, reduction will take place. As, cathode has a positive charge and it will be placed on left hand side.
Now,
= 0 and the general reaction equation is as follows.

3.00 M n = 2 30 mM
E = 
= 
= 0.038 V
Therefore, we can conclude that voltage shown by the voltmeter is 0.038 V.
Answer:
Option a → 4 mol NH₃
Explanation:
This the unbalanced reaction
NH₃ + O₂ ⟶ N₂ + H₂O
The balanced reaction:
4NH₃ + 3O₂ → 2N₂ + 6H₂O
4 mol of ammonia
3 mol of oxygen
2 mol of nitrogen
6 mol of water
Answer:
44.2 L
Explanation:
Use Charles Law:

We have all the values except for V₂; this is what we're solving for. Input the values:
- make sure that your temperature is in Kelvin
From here, we need to get V₂ by itself. To do this, multiply by 273 on both sides:

Therefore, V₂ = 44.2 L
It's also helpful to know that temperature and volume are linearly related. So, when temperature drops, so will volume and vice versa.
<span><span>Argon,</span><span>Carbon dioxide,</span><span>Neon,</span><span>Helium, and </span><span>Methane</span></span>
Hey there!
325 mL in liters:
325 / 1000 => 0.325 L
1 mole ( Ne ) ------------- 22.4 L ( at STP )
moles ( Ne ) ------------ 0.325 L
moles Ne = 0.325 * 1 / 22.4
moles Ne = 0.325 / 22.4
moles Ne = 0.0145 moles
hope this helps!